The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Word form:
Two and seven hundred eighty-nine thousandths
Expanded form:
2
+ 0.7
+ 0.08
+ 0.009
Answer:
nidE sme olome tib ary dae usa arajkpnoder xd jsaludos aja lpa
Step-by-step explanation:
Answer:
x=
y=5-
Step-by-step explanation:
x+y=5
y=5-x
x-y=a
x-(5-x)=a
2x-5=a
2x=a+5
x=
x+y=5
+y=5
y=5-
