4.0
i think it has something to do with molar ratios and finding the limiting reactant
4.0 mol NO * 2 mol NO2/2 mol NO = 4.0 moles of NO2
4.0 mol O2 * 2 mol NO2/1 mol O2 = 8.0 moles of NO2
so the limiting reactant (the reactant that runs out the quickest leaving an excess) is NO
once the limiting reactant is found, we can use that data for that substance to calculate the amount of product
4.0 mol NO * 2 mol NO2/2 mole NO = 4.0 moles of NO2
Answer:
hydrogen (H), nitogen (N), oxygen (O), fluorine (F), chlorine (Cl), helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn)
Explanation: found this online, it's best to remember them.
Explanation:
Atomic number (Z) = Number of the protons
It means that if the atomic number of C is 6, it implies that the number of protons in carbon is 6 too.
Mass number (M) = Number of the protons + Number of the neutrons
It means that if the atomic mass of C is 12, it implies that the number of protons and the neutrons in carbon is 12.