The pH of the final solution is
.
Further Explanation:
When extra amount of solvent is added, it results into dilution of concentrated solution but the amount of solute remains the same. There is a change in the volume of solution once dilution is done.
The following expression relates molarity and volume of dilute and concentrated solutions:
...... (1)
Here,
is the molarity of the concentrated solution.
is the volume of the concentrated solution.
is the molarity of a dilute solution.
is the volume of dilute solution.
Rearrange equation (3) to calculate
.
…… (2)
Substitute 2 M for
, 50 mL for
, 200 mL for
in equation (2) to calculate the concentration of
.
Substitute 2 M for
, 25 mL for
, 200 mL for
in equation (2) to calculate the concentration of
.

Henderson-Hasselbalch equation is a mathematical expression that is used to determine the of buffer solutions. The general expression for pH of buffer solution is as follows:
In the given system,
is a salt whereas
is an acid. So Henderson-Hasselbalch equation for the given system is as follows:
…… (3)
The value of
is 6.85.
The value of
is 0.5 M.
The value of
is 0.25 M.
Substitute these values in equation (3).
Learn more:
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Answer details:
Grade: High School
Subject: Chemistry
Chapter: Acid, base and salts.
Keywords: dilution, concentrated solution, pH, pKA, 0.5 M, 0.25 M, K2HPO4, KH2PO4, 6.85, 200 mL, 50 mL, 25 mL.