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3 years ago

Which element is the most reactive? sodium nickel carbon oxygen

Chemistry

1 answer:

leva [86]3 years ago

4 0

Sodium .

Atomic no-11
Electronic configuration= $\sf 1s^22s^23s^1$
Short name=Na
Latin name=Natrum
Period=3rd
Group=1st
Block=s-block

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How do you measure moles

wlad13 [49]

Answer:

Answers may vary

Explanation:

Mol is the amount of molecules in something. Mol are similar to donuts, if you have a dozen of something you have 12 of them. If you have a mol of Hydrogen gas you 6.02•10^23 molecules of Hydrogen gas. If you are taking a chemistry class you will probably receive questions involving converting grams to mol and vice versa.

Converting Grams to Mol:

grams of x•(1/molecular mass of x)

note: you can find molecular mass of x by looking at the masses of the elements you need to add up in the periodic table

Converting Mol to Grams:

mol of x•(molecular mass of x)

6 0

3 years ago

Read 2 more answers

Calculate how many grams of sodium azide (NaN3) are needed to inflate a 25.0 × 25.0 × 20.0 cm bag to a pressure of 1.35 atm at a

Luden [163]

Answer : The mass of $NaN_3$ at temperature $20^oC$ 28.47 g.

The mass of $NaN_3$ at temperature $10^oC$ 29.51 g.

Solution : Given,

Pressure of gas = 1.35 atm

Temperature of gas = $20^oC=273+20=293K$ $(0^oC=273K)$

Volume of gas = $25\times 25\times 20cm=12500cm^3=12.5L$ $(1L=1000cm^3)$

Molar mass of $NaN_3$ = 65 g/mole

Part 1 : First we have to calculate the moles of gas at temperature $20^oC$ . The gas produced in the given reaction is $N_2$ .

Using ideal gas equation,

$PV=nRT$

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

Now put all the given values in this formula, we get

$(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (293K)$

By rearranging the terms, we get the value of 'n'

$n=0.7015moles$

The moles of $N_2$ = 0.7015 moles

The given balanced reaction is,

$20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)$

As, 32 moles of $N_2$ produced from 20 moles of $NaN_3$

So, 0.7015 moles of $N_2$ produced from $\frac{20}{32}\times 0.7015=0.438$ moles of $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

$\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3$

$\text{ Mass of }NaN_3=(0.438moles)\times (65g/mole)=28.47g$

Therefore, the mass of $NaN_3$ needed are 28.47 g.

Part 2 : We have to calculate the moles of gas at temperature $10^oC$ and same volume & pressure.

Using ideal gas equation,

$PV=nRT$

Now put all the given values in this formula, we get

$(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (283K)$

By rearranging the terms, we get the value of 'n'

$n=0.726moles$

The moles of $N_2$ = 0.726 moles

The given balanced reaction is,

$20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)$

As, 32 moles of $N_2$ produced from 20 moles of $NaN_3$

So, 0.726 moles of $N_2$ produced from $\frac{20}{32}\times 0.726=0.454$ moles of $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

$\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3$

$\text{ Mass of }NaN_3=(0.454moles)\times (65g/mole)=29.51g$

Therefore, the mass of $NaN_3$ needed are 29.51 g.

7 0

3 years ago

Caffeine is used commercially as a(n):

Nataly [62]

I guess it would be a psychoactive substance i'm not really sure.. but i hope this helped

8 0

3 years ago

Which subatomic particle adds atomic mass to an atom but without adding charge? A. ion B. proton C. electron D. neutron

alexandr1967 [171]

Neutron is the answer, it has no charge

4 0

4 years ago

Read 2 more answers

What human activity constitutes to air pollution?

erastovalidia [21]

Answer:

ANSWER A: construction

5 0

4 years ago

Read 2 more answers