Question

What is the KE of a 13kg boulder moving at 78.3m/s?

Answer 1

Answer:

KE =

$\frac{1}{2} m {v}^{2}$

Explanation:

$ke = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} \times 13 \times {78 . 3}^{2} \\ ke = 39850.785j$

Answer 2

Answer:

39850.785 J

Explanation:

0.5 x m x v^2

0.5x13x78.3^2