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LuckyWell [14K]
3 years ago
12

What is the KE of a 13kg boulder moving at 78.3m/s?

Physics
2 answers:
Mrac [35]3 years ago
8 0

Answer:

KE =

\frac{1}{2} m {v}^{2}  \\

Explanation:

ke =  \frac{1}{2} m {v}^{2}  \\  =  \frac{1}{2}  \times 13 \times  {78 . 3}^{2}  \\ ke = 39850.785j \\

SIZIF [17.4K]3 years ago
5 0

Answer:

39850.785 J

Explanation:

0.5 x m x v^2

0.5x13x78.3^2

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