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GenaCL600 [577]
3 years ago
5

A small sphere that carries a charge q is whirled in a circle at the end of an insulating string. The angular frequency of rotat

ion is ω. What average current does this rotating charge represent? (Use any variable or symbol stated above as necessary.)
Physics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

i = qω/2π

Explanation:

Since the charge moves in a circle, its velocity v = rω. where r is the radius of the circle and ω the angular frequency of the charge.

The distance it covers in one cycle is the circle's circumference,d = 2πr.

The time it takes to cover this distance, t = d/v = 2πr/rω = 2π/ω

We know that current i = charge/time = q/t = q/2π/ω = qω/2π

So, the average current, i = qω/2π

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In asexual reproduction the new plant is identical to its parent.<br><br><br> true<br><br><br> false
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Answer:

YES

Explanation:

Asexual means the plant is identical to the parent

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Which of the following will cause an increase in gas pressure in a closed container?
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D. Both b and c is the answer
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You drive on Interstate 10 from San Antonio to Houston, half the time at 54 km/h and the other half at 118 km/h. On the way back
Irina-Kira [14]

Answer:

Average speed: 86 km/h

Explanation:

Driving from San Antonio to Houston:

1st. half time: 54km/h

2nd. half time: 118 km/h

Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h}  }{2}=86 \frac{km}{h} [\tex]

Driving way back:

1st. half time: 54km/h

2nd. half time: 118 km/h

Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h}  }{2}=86 \frac{km}{h} [\tex]

As in both routes we have the same average speed, then the average speed for the whole trip is 86 km/h

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4 years ago
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Suppose you push horizontally with precisely enough force to make the block start to move, and you continue to apply the same am
Tcecarenko [31]

Answer:

Incomplete question,

This is the complete question

Suppose you push horizontally with precisely enough force to make the block start to move, and you continue to apply the same amount of force even after it starts moving. Find the acceleration ~a of the block after it begins to move. Express your answer in terms of some or all of the variables µs, µk, and m, as well as the acceleration due to gravity g.

Explanation:

Let the force that make the object to start moving be F,

Frictional force is opposing the motion, the body has to overcome two frictional forces acting in the opposite direction of the motion.

Also, weight and normal reaction are acting in vertical direction, the weight is acting downward while the reaction is acting upward.

Weight of the object is given as

W=mg

Analyzing the vertical motion i.e y-axis.

ΣF = ma

since the body is not moving upward, the a=0

N-W=0

Then, N=W

So, N=mg

So, from friction law

Fr=µN

For static

Fs=µsN

For kinetic or dynamic

Fk= µkN

Using newton law

Along x-axis

Before the body start moving we can get the Force and since the force is the same use to start the block in motion.

Then,

ΣF = ma

Since at static the body is not moving then, a=0

F-Fs=0

F=Fs

Since, Fs=µsN

F=Fs=µsN

Then, the force to keep the body in motion too is F=µsN

Now analyses when the body is in motion

ΣF = ma

F-Fk=ma

ma=F - Fk

Substituting F=µsN and Fk=µkN

ma=µsN - µkN

ma=N(µs - µk)

Since N=mg

Then, ma=mg(µs - µk)

m cancels out, then

a=g(µs - µk)

Then the acceleration of the body is given as "a=g(µs - µk)"

5 0
3 years ago
What is the resulting velocity of the launcher if the net force on the launcher is equal to the reaction force?
xz_007 [3.2K]

Answer:

according to this question best answer is C

5 0
3 years ago
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