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brilliants [131]
2 years ago
6

4 1/3 + 6 2/5 Please show how you got the answer

Mathematics
1 answer:
ladessa [460]2 years ago
8 0

Answer:

Exact form: 161/15 Mixed Number Form: 10 11/15

Step-by-step explanation:

LOL

You might be interested in
A scale drawing of a rectangular park had a scale of 1 cm = 100 m.
Brilliant_brown [7]

Answer:

521,400 meters squared

Step-by-step explanation:

With the 1cm = 100m scale

6.6 cm = 660m

7.9 cm = 790m

Area = 660 x 790 = 521,400 meters squared

7 0
2 years ago
Write 169=13^2 in logarithmic form​
e-lub [12.9K]

Answer:

\log_{13}(169)=2

Step-by-step explanation:

The given exponential form is:

169=13^2

The base of the given expression on the right is 13 and the exponent is 2.

The number is 169.

In terms of logarithms, the base still remains the base and the exponent becomes the result of the logarithm of the number 169 to the given base 13.

\log_{13}(169)=2

4 0
2 years ago
Three friends were born in consecutive years. The some of their birth years is 5982.find the year in which each person was born
posledela
A+b+c=5982
find the average of the three friends 
5982/3=1994
add and subtract one to find the average 
1994+1=1995
1994-1=1993
add all the years together to check 
1993+1994+1995=5983
3 0
3 years ago
If the hypothesis is false, an argument cannot be valid, how would you explain this?
Elodia [21]
If the hypothesis was wrong, all you simply have to do is state the hypothesis was wrong and why you think it was, and add what you can do to change it or to make it better so next time it will be right. Just state what you did and how you got your answer.

I hope that helps!
8 0
3 years ago
            Find the approximate solution of this system of equations.
Montano1993 [528]
Y = |x² - 3x + 1|
y = x - 1

|x² - 3x + 1| = x - 1
|x² - 3x + 1| = ±1(x - 1)
|x² - 3x + 1| = 1(x - 1)       or      |x² - 3x + 1| = -1(x - 1)
|x² - 3x + 1| = 1(x) - 1(1)    or    |x² - 3x + 1| = -1(x) + 1(1)
|x² - 3x + 1| = x - 1        or         |x² - 3x + 1| = -x + 1
  x² - 3x + 1 = x - 1         or          x² - 3x + 1 = -x + 1
        - x        - x                                + x         + x
  x² - 4x + 1 = -1           or            x² - 2x + 1 = 1
              + 1 + 1                                       - 1 - 1
  x² - 4x + 1 = 0              or           x² - 2x + 0 = 0
  x = -(-4) ± √((-4)² - 4(1)(1))    or    x = -(-2) ± √((-2)² - 4(1)(0))
                      2(1)                                             2(1)
  x = 4 ± √(16 - 4)            or            x = 2 ± √(4 - 0)
                 2                                                 2
  x = 4 ± √(12)              or               x = 2 ± √(4)
             2                                                  2
 x = 4 ± 2√(3)               or               x = 2 ± 2
             2                                                2
 x = 2 ± √(3)                or                x = 1 ± 1
 x = 2 + √(3)  or  x = 2 - √(3)   or    x = 1 + 1    or    x = 1 - 1
                                                      x = 2       or       x = 0
y = x - 1          or           y = x - 1                            or    y = x - 1   or    y = x - 1
y = (2 + √(3)) - 1    or    y = (2 - √(3)) - 1          or         y = 2 - 1    or    y = 0 - 1
y = 2 - 1 + √(3)     or      y = 2 - 1 - √(3)          or           y = 1      or       y = -1
y = 1 + √(3)        or        y = 1 - √(3)               (x, y) = (2, 1)    or    (x, y) = (0, -1)
       (x, y) = (2 ± √(3), 1 ± √(3))

The solution (0, -1) can be made by one function (y = x - 1) while the solution (2 ± √(3), 1 ± √(3)) can be made by another function (y = |x² - 3x + 1|). So the solution (2, 1) can be made by both functions, making the two solutions equal.
4 0
3 years ago
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