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GenaCL600 [577]
3 years ago
7

Evaluate: cos ω, if tan ω = - 4/3 and sin ω > 0

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

-3/5

Step-by-step explanation:

tan = opp/adj using pathagorean the hypt is 5

cos = 3/5

tan is negative in quad 2 and 4

sin is positive in quad 1 and 2

so because tan is negative and sine is positive the cosine is negative

-3/5

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7/18 - 1/3 , 1/2 - 1/5 - 1/10 and 3 1/2 - 2 5/9 please help thank you ​
Dima020 [189]
1/18, 1/5,& 17/18

Hope these help!
3 0
3 years ago
H(t)=-16t^2+24t+40.0
TEA [102]

Answer:

t = -1 or 5/2

Step-by-step explanation:

To find t; we equate H(t) = 0

-16t^2+24t+40.0= 0

dividing through by 8 we have ;

-16t^2 / 8+ 24t/8+40.0/8=0

-2t^2 + 3t + 5=0

-2t^2 + 5t -2t + 5=0

By factorisation;

t(-2t + 5) +1 (-2t + 5)=0

This means;

(t + 1)(-2t +5)= 0

t + 1 = 0 or -2t + 5 = 0;

t= -1 ; -2t = -5

2t = 5

t = 5/2;

Hence t = -1 or 5/2

7 0
3 years ago
0.000147 in standard form
Otrada [13]
The answer is 1.47 x -10^-4 

4 0
3 years ago
Subtract and simplify Show work <br> (-5y^2-9y-4)-(-2y^2-y+8)
katrin2010 [14]

Answer:

-3y^2-8y-12

Step-by-step explanation:

3 0
3 years ago
Nuthin' to see here xd
lesya692 [45]

Answer:

lol what is ur question

5 0
4 years ago
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