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igor_vitrenko [27]
3 years ago
9

If f(x)=x^5+5x^3+4, what is the remainder when f(x) is divided by x-2?

Mathematics
1 answer:
Olin [163]3 years ago
6 0

By the polynomial remainder theorem, the remainder is

<em>f</em> (2) = 2⁵ + 5×2³ + 4 = 32 + 40 + 4 = 76

(The theorem says a polynomial <em>p(x)</em> has remainder <em>p(c)</em> upon dividing it by <em>x</em> - <em>c</em>.)

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frez [133]
(z+1.2)/5=3.6

quotient: division
3 0
3 years ago
If the value of a is negative in f(x)=ax^(2), what does the graph look like?
garik1379 [7]

Answer:

A. a parabola that opens down.

Step-by-step explanation:

First we can eliminate two answers, b and d, since parabalas that open left or right use the y variable.

Now the equation of a standard parabola is x². This means that there are no negative y values, and therefore it cannot open down, it is up.

With a NEGATIVE coefficient, the graph is flipped over the x axis, therefore making it open down.

Graphical proof is attached for further understanding, positive a is in red, negative a is in blue.

7 0
2 years ago
Read 2 more answers
A car is traveling at a rate of meters per second. What is the car's rate in kilometers per hour? How many kilometers will the c
jenyasd209 [6]

Answer:

- The car's rate in kilometers per hour is 108 kilometers per hour

- The car will travel 540 kilometers in 5 hours

Step-by-step explanation:

Here is the complete question:

A car is traveling at a rate of 30 meters per second. What is the car's rate in kilometers per hour? How many kilometers will the car travel in 5 hours? Do not round your answers.

Step-by-step explanation:

  • To determine the car's rate in kilometers per hour, we will convert 30 meters per second to kilometer per hour.

1000 meters = 1 kilometer

∴ 1 meter = 0.001 kilometer

3600 seconds = 1 hour

∴ 1 second = 1/3600 hour

Therefore,

30 meters/ second = \frac{30 \times 0.001 kilometer}{1/3600 hour}

= \frac{30 \times 0.001 \times 3600 kilometers}{1 hour}

= 108 kilometers / hour

Hence, the car's rate in kilometers per hour is 108 kilometers per hour.

  • To determine how many kilometers the car will travel in 5 hours, that is we are to determine the distance covered by the car in 5 hours.

From the formula

Speed = Distance / Time

∴ Distance = Speed × Time

(NOTE: Speed is also known as rate)

Speed (Rate) = 108 kilometers / hour

Time = 5 hours

∴ Distance = Speed × Time gives

Distance = 108 × 5

Distance = 540 kilometers

Hence, the car will travel 540 kilometers in 5 hours.

7 0
3 years ago
Need help asap please and thanks!​
antiseptic1488 [7]

Answer:

3 to 1

Step-by-step explanation:

Because the 6 is the bigger number but is also on the left which means the number on the right has to divide into the six therefore 3 to 1

6 0
4 years ago
Does anyone know how to do this? I’m confused
nikklg [1K]

Answer:

cos(θ)

Step-by-step explanation:

Para una función f(x), la derivada es el límite de  

h

f(x+h)−f(x)

​

, ya que h va a 0, si ese límite existe.

dθ

d

​

(sin(θ))=(  

h→0

lim

​

 

h

sin(θ+h)−sin(θ)

​

)

Usa la fórmula de suma para el seno.

h→0

lim

​

 

h

sin(h+θ)−sin(θ)

​

 

Simplifica sin(θ).

h→0

lim

​

 

h

sin(θ)(cos(h)−1)+cos(θ)sin(h)

​

 

Reescribe el límite.

(  

h→0

lim

​

sin(θ))(  

h→0

lim

​

 

h

cos(h)−1

​

)+(  

h→0

lim

​

cos(θ))(  

h→0

lim

​

 

h

sin(h)

​

)

Usa el hecho de que θ es una constante al calcular límites, ya que h va a 0.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)(  

h→0

lim

​

 

h

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)

Para calcular el límite lim  

h→0

​

 

h

cos(h)−1

​

, primero multiplique el numerador y denominador por cos(h)+1.

(  

h→0

lim

​

 

h

cos(h)−1

​

)=(  

h→0

lim

​

 

h(cos(h)+1)

(cos(h)−1)(cos(h)+1)

​

)

Multiplica cos(h)+1 por cos(h)−1.

h→0

lim

​

 

h(cos(h)+1)

(cos(h))  

2

−1

​

 

Usa la identidad pitagórica.

h→0

lim

​

−  

h(cos(h)+1)

(sin(h))  

2

 

​

 

Reescribe el límite.

(  

h→0

lim

​

−  

h

sin(h)

​

)(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

−(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

Usa el hecho de que  

cos(h)+1

sin(h)

​

 es un valor continuo en 0.

(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)=0

Sustituye el valor 0 en la expresión sin(θ)(lim  

h→0

​

 

h

cos(h)−1

​

)+cos(θ).

cos(θ)

5 0
3 years ago
Read 2 more answers
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