The IMA of the pulley shown is 2.
Answer:
0.5792g
Explanation:
The computation of the mass of the meter stick is shown below:
Let us assume the following items
x1 = 50 cm;
m2 = m3 = 3.62 g;
x2 = x3 = 20.3 cm;
xcm = 22.5 cm
Based on the above assumption, now we need to apply the equation of center mass which is given below:
27.5 m1 = 15.928
So, the m1 = 0.5792g
Answer:
A. <u>200m/s</u>
Explanation:
Using the law of conservation of momentum expressed as;
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the respective velocities
v is the common velocity
Given
m1 = 1.2kg
u1 = 0m/s (block is a stationary object)
m2 = 50g= 0.05kg
u2 = ?
v = 8.0m/s
Substitute the values into the formula and get u2 (speed of the bullet before hitting the block)
1.2(0)+0.05u2 = (1.2 + 0.05)(8)
0.05u2 = 1.25(8)
0.05u2 = 10
u2 = 10/0.05
u2 = 200m/s
Hence the speed of the bullet before it hit the block is <u>200m/s</u>
No, it can also be less than 1 depending on the class of the lever.
Answer:
This looks like an example of combustion
Explanation:
