Answer:
Zero
Explanation:
Two long parallel wires each carry the same current I in the same direction. The magnetic field in wire 1 is given by :
![B_1=\dfrac{\mu_oI_1}{2\pi r}](https://tex.z-dn.net/?f=B_1%3D%5Cdfrac%7B%5Cmu_oI_1%7D%7B2%5Cpi%20r%7D)
Magnetic force acting in wire 2 due to 1 is given by :
![F_{2}=I_2lB_1](https://tex.z-dn.net/?f=F_%7B2%7D%3DI_2lB_1)
![F_2=\dfrac{\mu_oI_1I_2 l}{2\pi r}](https://tex.z-dn.net/?f=F_2%3D%5Cdfrac%7B%5Cmu_oI_1I_2%20l%7D%7B2%5Cpi%20r%7D)
Similarly, force acting in wire 1 is given by :
According to third law of motion, the force acting in wire 1 will be in opposite direction to wire 2 as :
![F_2=-F_1](https://tex.z-dn.net/?f=F_2%3D-F_1)
So, the total magnetic field at the point P midway between the wires is in what direction will be zero as the the direction of forces are in opposite direction.
Answer:
remains the same, but the apparent brightness is decreased by a factor of four.
Explanation:
A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.
It is typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He).
The luminosity of a star refers to the total amount of light radiated by the star per second and it is measured in watts (w).
The apparent brightness of a star is a measure of the rate at which radiated energy from a star reaches an observer on Earth per square meter per second.
The apparent brightness of a star is measured in watts per square meter.
If the distance between us (humans) and a star is doubled, with everything else remaining the same, the luminosity remains the same, but the apparent brightness is decreased by a factor of four (4).
Some of the examples of stars are;
- Canopus.
- Sun (closest to the Earth)
- Betelgeuse.
- Antares.
- Vega.
1) At the moment of being at the top, the piston will not only tend to push the penny up but will also descend at a faster rate at which the penny can reach in 'free fall', in that short distance. Therefore, at the highest point, the penny will lose contact with the piston. Therefore the correct answer is C.
2) To solve this problem we will apply the equations related to the simple harmonic movement, hence we have that the acceleration can be defined as
![a = -\omega^2 A](https://tex.z-dn.net/?f=a%20%3D%20-%5Comega%5E2%20A)
Where,
a = Acceleration
A = Amplitude
= Angular velocity
From a reference system in which the downward acceleration is negative due to the force of gravity we will have to
![a = -g](https://tex.z-dn.net/?f=a%20%3D%20-g)
![-\omega^2 A = -g](https://tex.z-dn.net/?f=-%5Comega%5E2%20A%20%3D%20-g)
![\omega = \sqrt{\frac{g}{A}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cfrac%7Bg%7D%7BA%7D%7D)
From the definition of frequency and angular velocity we have to
![\omega = 2\pi f](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f)
![f = \frac{1}{2\pi} \sqrt{\frac{g}{A}}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B2%5Cpi%7D%20%5Csqrt%7B%5Cfrac%7Bg%7D%7BA%7D%7D)
![f = \frac{1}{2\pi} \sqrt{\frac{9.8}{4*10^{-2}}}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B2%5Cpi%7D%20%5Csqrt%7B%5Cfrac%7B9.8%7D%7B4%2A10%5E%7B-2%7D%7D%7D)
![f = 2.5Hz](https://tex.z-dn.net/?f=f%20%3D%202.5Hz)
Therefore the maximum frequency for which the penny just barely remains in place for the full cycle is 2.5Hz
Answer:
Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics. It was formulated by Archimedes of Syracuse.
Answer:
the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg
Explanation:
Total heat content of the fat = heat content of water +heat content of the lipids
Let it be Q
the Q= (mcΔT)_lipids + (mcΔT)_water
total mass of fat M= 0.63 Kg
Q= heat supplied = 100 W in 5 minutes
ΔT= 20°C
c_lipid= 1700J/(kgoC)
c_water= 4200J/(kgoC)
then,
![100\times5\times60= m(1700)20+(0.63-m)(4200)20](https://tex.z-dn.net/?f=100%5Ctimes5%5Ctimes60%3D%20m%281700%2920%2B%280.63-m%29%284200%2920)
solving the above equation we get
m= 0.46 kg
the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg