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victus00 [196]
3 years ago
9

An electron moves at a speed of 1000 m/s perpendicular to the direction of a uniform magnetic field of 0.5 T. What is the radius

of the electron's circular orbit in units of nanometers (1 m

Physics
2 answers:
Ugo [173]3 years ago
8 0

Answer:

11.4 nm

Explanation:

The magnetic force drives the circular motion of the electron.

Magnetic force on a charge, q, moving with velocity, v, in a magnetic field, B, moving at angle θ to the field is given by

F = qvB sin θ⁻⁰¹²³⁴⁵⁶⁷⁸⁹

q = charge on an electron = - 1.6 × 10⁻¹⁹ C

v = velocity of the electron = 1000 m/s

B = 0.5 T

Sin θ = sin 90° = 1

F = 1.6 × 10⁻¹⁹ × 1000 × 0.5 = 8.0 × 10⁻¹⁷ N

This force drives the circular motion

F = mv²/r

m = mass of an electron = 9.11 × 10⁻³¹ kg

v = 1000 m/s, r = radius of orbit = ?

8 × 10⁻¹⁷ = (9.11 × 10⁻³¹ × 1000²)/r

r = (9.11 × 10⁻³¹ × 1000²)/(8 × 10⁻¹⁷) = 1.14 × 10⁻⁸ m = 11.4 nm

Vsevolod [243]3 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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Answer:

Electrons are so small that it does not affect the mass of atom .

Explanation:

Electrons are much smaller in mass than protons, weighing only 9.11 × 10^-28 grams, or about 1/1800 of an atomic mass unit. Therefore, they do not contribute much to an element's overall atomic mass.

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The acceleration due to gravity of the moon is 1.67
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Answer:

I think it's 1.625 m/s2

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3 years ago
An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary
Alenkinab [10]

Answer:

T =  4200N

Explanation:

When the submersible craft is at rest, the tension in the cable is 6000N.

With this information you can calculate the weight of the craft by summing the forces (the summation of the force is zero because the craft is at rest):

T-W=0\\\\W=T=6000N

When the craft is going down with a constant speed, there is a drag force of 1800N. Then, by using the second Newton law you have:

T-W+F_d=0   (1)

Fd: drag force

The summation of the forces is zero because the craft moves with constant velocity, that is, there is no acceleration.

You calculate the new tension on the cable by solving the equation (1) for T:

T=W-Fd=6000N-1800N=4200N

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5 0
3 years ago
IN THIS FORMULA FOR WATER WHAT DOES THE SUBSCRIPT 2 INDICATE
masha68 [24]
The chemical formular for water is H2O.
The H aspect of the formula stands for hydrogen gas and the subscript 2 which is attached to the H symbol signifies that two atoms of hydrogen are joined together, that is two atom of hydrogen are present.
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7 0
4 years ago
A nonconducting solid sphere of radius 11.6 cm has a uniform volume charge density. The magnitude of the electric field at 23.2
3241004551 [841]

Answer: a) 1.76 μC/m^3 ; b) 40.73 * 10^3 N/C

Explanation: In order to solve this problem we have to use the  Gaussian law, in this sense we have:

∫E.dS= Q inside/εo then we have:

E* 4*π*r= ρ* Volume/εo

then

ρ= E4*π* εo*r^2/Volume)= E*r^2/(k*(4/3)*π*R^3)  where R is the radius of the sphere

ρ= 0.232^2*1,89*10^3/(6.54* 10^-3*9*10^9)=1.76 μC/m^3

The electric field is given by:

E= k*Vol*ρ/r^2  for r= 5cm

E= 9*10^9*6.54~ 10^-3* 1.73*10^-6/(0.0025)=40.73 * 10^3 N/C

5 0
3 years ago
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