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victus00 [196]
3 years ago
9

An electron moves at a speed of 1000 m/s perpendicular to the direction of a uniform magnetic field of 0.5 T. What is the radius

of the electron's circular orbit in units of nanometers (1 m

Physics
2 answers:
Ugo [173]3 years ago
8 0

Answer:

11.4 nm

Explanation:

The magnetic force drives the circular motion of the electron.

Magnetic force on a charge, q, moving with velocity, v, in a magnetic field, B, moving at angle θ to the field is given by

F = qvB sin θ⁻⁰¹²³⁴⁵⁶⁷⁸⁹

q = charge on an electron = - 1.6 × 10⁻¹⁹ C

v = velocity of the electron = 1000 m/s

B = 0.5 T

Sin θ = sin 90° = 1

F = 1.6 × 10⁻¹⁹ × 1000 × 0.5 = 8.0 × 10⁻¹⁷ N

This force drives the circular motion

F = mv²/r

m = mass of an electron = 9.11 × 10⁻³¹ kg

v = 1000 m/s, r = radius of orbit = ?

8 × 10⁻¹⁷ = (9.11 × 10⁻³¹ × 1000²)/r

r = (9.11 × 10⁻³¹ × 1000²)/(8 × 10⁻¹⁷) = 1.14 × 10⁻⁸ m = 11.4 nm

Vsevolod [243]3 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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Part A : 4.33 Volt.

Part B : 4764 Amperes.

Given Data :  

Field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs.

Axis of his 2.1-cm-diameter wedding band is parallel to the field.

Part A :

induced emf = rate of change of magnetic flux

= d (B A )/dt

= A dB/dt

= { π (2.1 x 10^-2 / 2)^2) (2.5) } / (200 x 10^-6)

E = 4.33 Volt

Part B :

R = rho L / A

R = { (6.2 x 10^-8) ( π x 0.021) } / (4.5 x 10^-6)

R = 9.10 x 10^-4 Ohm

We know, (I = V/ R)

I = 4.33 Volts / 9.10 x 10^-4 Ohm

I = 4764 Amperes

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➤ Although your question isn't complete, I may have assumed that you were referring to this specific question.

The complete question is :

A TMS (transcranial magnetic stimulation) device creates very rapidly changing magnetic fields. The field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs. Suppose a technician holds his hand near the device so that the axis of his 2.1-cm-diameter wedding band is parallel to the field.

Part A: What emf is induced in the ring as the field changes? Express your answer to two significant figure E= ___ unit_

Part B: If the band is made of a gold alloy with resistivity 6.2×10−8Ω⋅m and has a cross-section area 4.5 mm2 , what is the induced current? Express your answer to two significant figures and include the appropriate units. I= ___ units__

6 0
2 years ago
A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves o
aniked [119]

Correct question is;

A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves offers a damping force numerically equal to √2 times the instantaneous velocity. Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 7 ft/s. (Use g = 32 ft/s²)

Answer:

x(t) = 7te^(-2t√2)

Explanation:

We are given;

Weight; W = 8 lbs

mass; m = W/g

g = 32 ft/s²

Thus;

m = 8/32

m = ¼ slugs

From Newton's second law we can write the equation as;

m(d²x/dt²) = -kx - β(dx/dt)

Rearranging this, we have;

(d²x/dt²) + (β/m)(dx/dt) + (k/m)x = 0

Where;

β is damping constant = √2

k is spring constant = W/s

Where s = 8ft - 4ft = 4ft

k = 8/4

k = 2

Thus,we now have;

(d²x/dt²) + (√2/(¼))(dx/dt) + (2/(¼))x = 0

>> (d²x/dt²) + (4√2)dx/dt + 8x = 0

The auxiliary equation of this is;

m² + (4√2)m + 8 = 0

Using quadratic formula, we have;

m1 = m2 = -2√2

The general solution will be gotten from;

x_t = c1•e^(mt) + c2•t•e^(mt)

Plugging in the relevant values gives;

x_t = c1•e^(mt) + c2•t•e^(mt)

At initial condition of t = 0, x_t = 0 and thus; c1 = 0

Also at initial condition of t = 0, x'(0) = 7 and thus;

Since c1 = 0, then c2 = 7

Thus,equation of motion is;

x(t) = 7te^(-2t√2)

8 0
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Katen [24]
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Answer:

d = 69 .57 meter

Explanation:

First case

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Second case

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d = ?

Work done = 0.5 * 22.44² * m J = 251.7768 * m J

Since the braking force remains the same .

3.619 m = ( 251.7768 m / d )

d = 69 .57 meter

7 0
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