Answer:
impedance Z = 416.66 ohm
voltage across inducance V = 346.99 V
power factor = 0.720
Explanation:
given data
resistor R = 300
voltage amplitude = 500 V
resistor = 216 W
to find out
impedance and amplitude of the voltage and power factor
solution
we apply here average power formula that is
average power = I²×R ............1
I =
so
average power = (
)²×R
Vrms =
× Vmax
Z = V ×
Z = 500 ×
impedance Z = 416.66 ohm
and
we know voltage across inductor is here express as
V = I × X .............2
so here X will be by inductance
Z² = R² + (X)²
(X)² = 416.66² - 300²
X = 289.15 ohm
and I = 
I = 
I = 1.20 A
so from equation 2
V = 1.20 × 289.15
voltage across inducance V = 346.99 V
and
average power = Vmax × Imax × cos∅
tan∅ = 
tan∅ = 43.95°
so power factor is
power factor = cos43.95°
power factor = 0.720
The answer for the following problem is mentioned below.
- <u><em>Therefore the time period is 0.02 seconds.</em></u>
Explanation:
Frequency:
The number of waves that pass a fixed place in a given amount of time. (or)
The number of waves that pas by per second.
The SI unit of the frequency is Hertz(Hz).
Time period:
The time taken for one complete cycle of vibration to pass a given point.
The SI unit of time period is seconds. (s)
Given:
Frequency (f) = 39.5 Hz
To calculate:
Time period (T)
We know;
According to the problem;
From the problem;
<u>f = </u>
<u></u>
Where;
f represents the frequency
T represents the time period
f = 
f = 0.02 seconds
<u><em>Therefore the time period is 0.02 seconds.</em></u>
I think when particles are in the gas form they are most likely to cause a chemical reaction considering the fact that gas particles aren't very controllable and it would make sense that they would react unexpectedly
Recall that to compute for the emf of a circuit given current and inductance, we must recall that

where I is the current (A), M is the mutual inductance (h), and t is the time (ms). Since the current must not exceed 80.0 V, we have



From this, we see that it must take at least 0.35 ms so it doesn't exceed 80 V.
Answer: 0.35 ms
The object will continue moving in a straight line at constant speed.