Answer:
Wave A
<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>
Seismic waves are waves generated by Earthquakes.
Explanation:
For equilibrium,
.
So,
= 0
![T_{1} = \frac{8 \times mg}{10}](https://tex.z-dn.net/?f=T_%7B1%7D%20%3D%20%5Cfrac%7B8%20%5Ctimes%20mg%7D%7B10%7D)
= ![\frac{8 \times 90 \times 9.8}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B8%20%5Ctimes%2090%20%5Ctimes%209.8%7D%7B10%7D)
= 705.6 N
Also, for equilibrium
= 0
= 0
or, ![T_{2} = mg - T_{1}](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20mg%20-%20T_%7B1%7D)
= ![90 \times 9.8 - 705.6](https://tex.z-dn.net/?f=90%20%5Ctimes%209.8%20-%20705.6)
= 176.4 N
Thus, we can conclude that the tension in the first rope is 176.4 N.
Answer:
k = 3.5 N/m
Explanation:
It is given that the time period the bob in pendulum is the same as its time period in spring mass system:
![Time\ Period\ of\ Pendulum = Time\ Period\ of\ Spring-Mass\ System\\2\pi \sqrt{\frac{l}{g}} = 2\pi \sqrt{\frac{m}{k}](https://tex.z-dn.net/?f=Time%5C%20Period%5C%20of%5C%20Pendulum%20%3D%20Time%5C%20Period%5C%20of%5C%20Spring-Mass%5C%20System%5C%5C2%5Cpi%20%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%7D%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Bm%7D%7Bk%7D)
![\frac{l}{g} = \frac{m}{k}\\\\ k = g\frac{m}{l}](https://tex.z-dn.net/?f=%5Cfrac%7Bl%7D%7Bg%7D%20%3D%20%5Cfrac%7Bm%7D%7Bk%7D%5C%5C%5C%5C%20k%20%3D%20g%5Cfrac%7Bm%7D%7Bl%7D)
where,
k = spring constant = ?
g = acceleration due to gravity = 9.81 m/s²
m = mass of bob = 125 g = 0.125 kg
l = length of pendulum = 35 cm = 0.35 m
Therefore,
![k = (9.81\ m/s^2)(\frac{0.125\ kg}{0.35\ m})\\\\](https://tex.z-dn.net/?f=k%20%3D%20%289.81%5C%20m%2Fs%5E2%29%28%5Cfrac%7B0.125%5C%20kg%7D%7B0.35%5C%20m%7D%29%5C%5C%5C%5C)
<u>k = 3.5 N/m</u>
Answer: 2 seconds
Explanation:
Given that,
Time (T) = ?
Charge (Q) = 4 coulombs
current (I) = 2 Amps
Since charge depends on the amount of current flowing through the wire in a given time, hence
Charge = Current x Time
Q = IT
4 coulombs = 2 Amps x Time
Time = 4 coulombs / 2 Amps
Time = 2 seconds
Thus, it takes 2 seconds for the current to flow through the wire