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IRISSAK [1]
3 years ago
12

When you stand on tiptoes on a bathroom scale, there is an increase in

Physics
1 answer:
pychu [463]3 years ago
3 0

Answer:

B) Pressure on the scale, not registered as weight.

Explanation:

This is because energy (derived from weight) becomes compiled on the tips of your toes, and therefore does not increase your weight, but simply the pressure at a smaller point

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A car has a mass of 1.20 x 10^3 kilograms and a momentum of 2.00 x 10^4 kilogram meters/second. What is the velocity of the car?
lorasvet [3.4K]
The answer will be v=16.7m/s
I hope this helps you, have a great day!
5 0
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Whitch family has full valence energy level
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Group 0 - they are called the NOBLE GASES
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ALL of their atoms are full.
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A cruise took 6 hours to fulfill its trip. It travelled at an average
kramer

Answer: 1035

Explanation:

4 0
3 years ago
1. As a swimmer jumps off a 10.0 m high diving board, they start to accelerate towards the
stich3 [128]

Answer:

1960 J

Explanation:

Potential energy is given as the product of mass, height and acceleration due to gravity and expressed as mgh where m represent the mass of the swimmer, g is acceleration due to gravity and h is the height. Since the swimmer has just gone 4 m from the surface, that is the height that potential energy is converted to kinetic energy. This follows the law of transformation of energy since the energy can't be lost but rather transformed from one state to another. Therefore, substituting 50 kg for m, 4 m for h and 9.8 for g we obtain that PE=50*4*9.8=1960 J. Since it's not among the options here, maybe it is option D

6 0
3 years ago
A copper wire has radius 0.800 mm and carries current I at 20.0°C. A silver wire with radius 0.500 mm carries the same current a
IgorC [24]

Answer:

Ecu/Eag = 0.46

Explanation:

E = PI/A

Ecu = Pcu × I/A

Pcu = 1.72×10^-8 ohm-meter

r = 0.8 mm = 0.8/1000 = 8×10^-4 m

A = πr^2 = π×(8×10^-4)^2 = 6.4×10^-7π

Ecu = 1.72×10^-8I/6.4×10^-7π = 0.026875I/1

Eag = Pag × I/A

Pag = 1.47×10^-8 ohm-meter

r = 0.5 mm = 0.5/1000 = 5×10^-4 m

A = πr^2 = π × (5×10^-4)^2 = 2.5×10^-7π

Eag = 1.47×10^-8I/2.5×10^-7π = 0.0588I/π

Ecu/Eag = 0.026875I/π × π/0.0588I = 0.46

7 0
3 years ago
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