Answer:
Height is 11.25m
Explanation:
<u>Given the following data;</u>
Initial velocity, u = 0
Final velocity, v = 15m/s
Acceleration due to gravity, g = 10m/s²
To find the height, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
- S represents the displacement (height) measured in meters.
<em>Making S the subject, we have;</em>

But a = g = 10m/s²
<em>Substituting into the equation, we have;</em>

S = 11.25m
<em>Therefore, the ball will reach a height of 11.25m before it begins to fall. </em>
The law that accounts for that exact statement is the law that says that
most people don't understand these things very well.
A better statement is:
<span>"The gravitational forces between the Sun and each planet cause each planet
to move in an elliptical path."<span>
The laws that account for that behavior are:
-- Newton's second law of motion: (Force) = (mass) x (acceleration)
-- Newton's law of universal gravity</span></span>
The speed will increase, as there is acceleration, while the acceleration will remain constant, as gravity is constant.
During a car crash, energy is transferred from the vehicle to whatever it hits, be it another vehicle or a stationary object. ... The object that was struck will either absorb the energy thrust upon it or possibly transfer that energy back to the vehicle that struck it.
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