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svetoff [14.1K]

2 years ago

10

It takes Zach 15 minutes to walk 7 1/2 blocks to the swimming pool. At this rate, how many blocks can he walk in one minute? Cir

cle the letter of the correct answer.
Dee chose c as the correct answer. What was her error?

What was her error?

1 answer:

zimovet [89]2 years ago

3 0

Answer:

mathmodemathmodemathmodemathmodemathmode

Step-by-step explanation:

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U=1-3v/vt-w make t the subject<br> Answer for it

Oxana [17]

Answer:

t= - $\frac{u}{3}$ + $\frac{1}{3}$ - $\frac{w}{3}$

Step-by-step explanation:

Divide each side with variables by the one without them.

4 0

2 years ago

Can anyone help me with this?

erma4kov [3.2K]

Answer: 16y² - x²

Step-by-step explanation: The - sign means a difference, so the choices with + signs are eliminated (though 64x² and 9 are squares)

10 is not a square so that one is eliminated (though the y² and the 4x² are squares)

16 is the square of 4, y² is the square of y, and x² is the square. That expression shows a difference of squares.

3 0

3 years ago

3 (x- 4) = 2 (x+1)<br><br> Justification reason

Murrr4er [49]

Solution

=14

Step-by-step explanation:

<h2>3x-12=2x+2</h2><h2>3x-12=2x+23x-2x-12=2</h2><h2>3x-12=2x+23x-2x-12=2x=12+2</h2><h2>3x-12=2x+23x-2x-12=2x=12+2x=14</h2>

5 0

2 years ago

PLEASE HELP WILL BRAINLIST IF RIGHT

Kazeer [188]

Answer:4, -1

Step-by-step explanation:

8 0

2 years ago

There are three executives in an office, ages 56, 57, and 58. If a 57-year-old executive enters the room, the

vova2212 [387]

Answer:

option (c) The mean age will stay the same but the variance will decrease

Step-by-step explanation:

Case I: For 3 executives of ages 56, 57 and 58

Number of executives, n = 3

Mean = $\frac{\textup{56 + 57 + 58 }}{\textup{3}}$

or

Mean = 57

Variance = $\frac{\sum{(Data - Mean)^2}}{\textup{n-1}}$

or

Variance = $\frac{(56 - 57)^2+(57-57)^2+(58-57)^2}{\textup{3-1}}$

or

Variance = $\frac{1+0+1}{\textup{2}}$

or

Variance = 1

For Case II: For 4 executives of ages 56, 57, 58 and 57

Number of executives, n = 4

Mean = $\frac{\textup{56 + 57 + 58 + 57 }}{\textup{4}}$

or

Mean = 57

Variance = $\frac{\sum{(Data - Mean)^2}}{\textup{n-1}}$

or

Variance = $\frac{(56 - 57)^2+(57-57)^2+(58-57)^2+(57-57)^2}{\textup{4-1}}$

or

Variance = $\frac{1+0+1+0}{\textup{3}}$

or

Variance = 0.67

Hence,

Mean will remain the same and the variance will decrease

Hence,

The correct answer is option (c) The mean age will stay the same but the variance will decrease

3 0

2 years ago