The values of b and c are -4 and 4 respectively
<h3>How to determine the values of b and c?</h3>
The function is given as:
f(x) = x^2 + bx + c
Differentiate f(x)
f'(x) = 2x + b
Set to 0
2x + b = 0
Solve for b
b = -2x
The minimum is (2, 0).
So, we have:
b = -2 * 2
b = -4
Substitute b = -4 in f(x) = x^2 + bx + c
f(x) = x^2 - 4x + c
Substitute (2, 0)
0 = (2)^2 - 4(2) + c
This gives
0 = 4 - 8 + c
Evaluate
c = 4
Hence, the values of b and c are -4 and 4 respectively
Read more about functions at:
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Step-by-step explanation:
The general form of a straight line is y = mx + c, where m is the line's slope and c is the y-intercept.
For y = 3x + 2, the slope is positive 3 and the y-intercept is 2. The line should rise up and pass through the point (0, 2).
We are between Options B and C.
In Graph B, the line raises by 4 units for every 2 units across. Hence its slope is 4/2 = 2.
In Graph C, the line raises by 3 units for every 1 unit across. Hence its slope is 3/1 = 3.
Since we want 3 as the slope,
The answer is Option C.
Answer:
22
Step-by-step explanation:
10/2 $5 per pack
110/5= 22 packs
Answer:
B
Step-by-step explanation:
This is the correct answer ;)
If the circumference of a circle was, for example, 25, to find the diameter, well have to divide 25 from pie to get it.
The answer would've been <em>7.957747</em><em>.</em><em> </em>
Therefore B is the right answer :)
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