Answer:
Electrostatic phenomenon is a from the forces that electric charges exert on each other.
For the crate moving along the direction of Force with constant velocity the summation of the force alng x-axis should be zero. and too for the y component
In view of this
Fx=Fcos30
=364.4N
Answer:
See explanation below
Explanation:
In this case, you want to know if you put an object between these forces, which direction would go.
To know this, we need to calculate the moment of an object, which is defined as the product of a force and it's distance. In other words:
M = F * d (1)
And, in order to reach equilibrium the force will exert a direction in clockwise or anticlosewise, and these moments, should be even:
anticlockwise moment = clockwise moment.
The clockwise would be the forces to the right, and anticlock would the only force to the left of the axle.
Clockwise moment = (10 * 0.8) + (25 * 2.6) = 73 Ns
Anticlockwise moment = 34 * 3.5 = 119 Ns.
As we can see, the moment in the anticlockwise is higher than the actual clockwise moment, therefore, we can assume that the object will move anticlockwise, or simply move to the left.
Hope this helps
The control group is the independent variable and the experimental group is the dependent due to change during the experiment. The experimental group will usually rely on another variable in the experiment for change.
<u>Answer:</u>
Positive acceleration is in third hour and negative acceleration is in second hour.
<u>Explanation:</u>
Velocity of car in first hour = 70 mph
Velocity of car in second hour = 60 mph
Velocity of car in third hour = 80 mph
Acceleration = Change in velocity / Time
Acceleration in second hour = (60 - 70)/1 = -10 mph²
Acceleration in third hour = (80 - 60)/1 = 20 mph²
So positive acceleration is in third hour and negative acceleration is in second hour.
