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Likurg_2 [28]
3 years ago
15

Having trouble doing these questions on forces on how to do them, this is urgent does anyone have any tips to tackle these quest

ions?

Physics
1 answer:
77julia77 [94]3 years ago
3 0

Answer:

I have no idea but good luck !!

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It would cause the lens to produce only real images. It would cause the lens to produce only virtual images. It would make the lens stronger. It would make the lens weaker.

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A rock is thrown from a height of 2.0 m at a window that is located 9.0 m above the ground. The initial velocity of the rock is
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Answer:

The value is  x = 11.81 \ m

Explanation:

From the question we are told that

   The height is h =  2.0 m

   The height of the window is d = 9.0 \ m

    The initial velocity of the rock is u =  20 \ m/s

    The angle at which it is thrown is \theta  =  40

Generally the  vertical component of the velocity of the stone is mathematically represented as

    v_y = 20 sin (40)

=>v_y = 12.86 \ m/s

Generally the height of the window from the ground is mathematically represented as using kinematic equation as

      d = h  +  v_yt + \frac{1}{2} gt^2

=>   9 = 2  +12.86 t + \frac{1}{2} * - 9.8 t^2

Here g is negative -9.8 m/s^2 because the direction of the stone is against gravity

   So

       4.9 t^2 -12.86 t + 7 =0

Solving this quadratic equation using quadratic formula we obtain

     t = 0.770 s

Generally the velocity of the stone on the x axis is mathematically represented as

       v_x =  20 * cos(40 )

=>    v_x =  15.32 \  m/s

Generally the distance between the person throwing the rock and the window is mathematically represented as

       x =  v_x * t

=>    x =  15.32 * 0.771

=>    x = 11.81 \ m

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The answer to this is: a molecule
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