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yaroslaw [1]
4 years ago
10

Which of the following is a good example of a physical change?

Physics
1 answer:
den301095 [7]4 years ago
5 0
Candle burning because it’s going from a solid to a liquid

Plz give me a good mark
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An initially uncharged air-filled capacitor is connected to a 2.63 V charging source. As a result, 6.27×10−5 C of charge is tran
user100 [1]

Answer:

Charge stored after insertion will be 22.257\times 10^{-5}C

Explanation:

We have given potential difference V =2.63 V

Q_0= charge stored by the capacitor when without dielectric = 6.27\times 10^{-5}C

We know that Q_0=C_0V, here C_0 is capacitance without dielectric

6.27\times 10^{-27}=2.63\times C_0

C_0=2.384\times 10^{-5}F

We have given

k = dielectric constant = 5.99

C = Capacitance with the dielectric = kC_0 = 3.55×2.384\times 10^{-5} = 8.463\times 10^{-5}F

Potential difference is due to the external charging source so it remains same

V = potential difference after insertion = 2.63 volts

New charge stored , Q=CV=8.463\times 10^{-5}\times 2.63=22.257\times 10^{-5}C

7 0
4 years ago
An object's inertia causes it to come to a rest position.<br> TRUE OR FAULSE
Iteru [2.4K]
FAULSE!!!!!
false^
learn basic spelling bro
7 0
4 years ago
A deep-space probe moves away from Earth with a speed of 0.51 c. An antenna on the probe requires 3.9 s (probe time) to rotate t
QveST [7]

Answer:

Time required for 1.5 rev for an observer on earth = 7.24 s

Given:

velocity of probe, v = 0.51 c

t_{1} = 3.9 s

Solution:

Using Einstein's theory of relativity for time dilation:

t = \frac{t_{1}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}

where

t = observed time on earth

Now,

t = \frac{3.9}{\sqrt{1 - \frac{(0.59c)^{2}}{c^{2}}}} = 4.83 s

Now, time required for 1.5 rev:

t = 1.5\times 4.83 = 7.24 s

5 0
4 years ago
The gravitational attraction between a large object and a small object is...
Marina86 [1]

Answer:

A) Greater than the attraction between two small objects the same distance apart.

Explanation:

The gravitational force between two objects is:

F = GMm / r²

where G is the gravitational constant,

M is the mass of one object,

m is the mass of the other object,

and r is the distance between the objects.

If the distance is the same, then two large objects will have a larger gravitational force between them than two small objects.

5 0
3 years ago
Can u read a ruler it's very hard
iris [78.8K]

Answer:

A. 1 inch

B. 1/2 inch

C. 3/4 inch

D. 1/8 inch

E. 1 7/8 inch

F. 1 1/2 inch

G. 3 1/15 inch

H. 2 5/8 inch

I. 2 1/4 inch

8 0
3 years ago
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