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coldgirl [10]
2 years ago
9

A 1kg mass is thrown to a height of 2cm. what is the potential energy​

Physics
2 answers:
prohojiy [21]2 years ago
4 0
  • Mass=m=1kg
  • Height=h=2cm=0.02m
  • Acceleration due to gravity=g=10m/s^2

\\ \tt\hookrightarrow P.E=mgh

\\ \tt\hookrightarrow PE=1(10)(0.02)

\\ \tt\hookrightarrow PE=0.2J

Andreyy892 years ago
3 0
<h2><u>POTENTIAL </u><u>ENERGY</u></h2>

<h3>Question:</h3>

A 1 kg mass is thrown to a height of 2cm. What is the potential energy?

<h3>Answer:</h3>
  • \color{hotpink}{  \bold{0.196  \:  \: J}}

— — — — — — — — — —

<h3>Formula:</h3>

— To calculate the potential energy, use formula

  • \underline{ \boxed{ \tt PE=mgh}}

where,

  • PE is the potential energy in joules (J)
  • m is the mass in kilograms (kg)
  • g is the acceleration due to gravity (9.8 m/s²)
  • h is the height in meters (m)

- To calculate the potential energy, multiply all the givens.

<h3>Given that:</h3>
  • m (mass) = 1 kg
  • g = 9.8 m/s²
  • h (height) = 2 cm

— To get the P.E (potential energy), we need to convert 2 cm (centimeters) in m (meters) first.

All we know that 1 cm is equal to 0.01 meter. So, to get the value of 2 cm in meters, all we have to do is to multiply it by 0.01.

  • \tt \:  2  \times 0.01 =  \underline{ \boxed{ \purple{ \tt0.02}}}
<h3 /><h3>Solution:</h3>

— Substitute the givens in the formula, we get:

  • \tt \: PE = mgh \\

  • \tt   PE= (1 kg) × (9.8 m/s²) × (0.02 m) \\

  • \tt PE = \underline{ \boxed{ \blue{ \tt0.196  \: J }}} \\

Hence, the potential energy is <u>0.196 Joules</u>.

_______________∞_______________

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It would mean that, after collision, momentum of the system is equal to the initial momentum.

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