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Diano4ka-milaya [45]
3 years ago
14

Balls A and B are thrown at the same angle from the ground, with an initial velocity for Ball A

Physics
1 answer:
iragen [17]3 years ago
5 0

Answer:

Ball with the initial velocity as 15m/s will reach larger distance horizontally on the  ground.

Explanation:

Ball 'A' has less initial velocity compared to ball 'B'. Which means it will take more time to reach horizontally on the ground. Therefore, Ball 'A' will cover larger distance.

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The hydronium ion concentration in an aqueous solution is [H+] = 5.3 x10-4 M. What is the hydroxide ion concentration? Is this s
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6 0
3 years ago
Satellite A is orbiting Earth at an altitude of 500 km and Satellite B is orbiting 800 km above the surface . How does the veloc
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The velocity of Satellite A is 2% greater than velocity of satellite B.

The given parameters;

  • <em>Altitude of Satellite A = 500 km</em>
  • <em>Altitude of Satellite B = 800 km</em>

The forces acting on the Satellites are given as follows;

F_c = \frac{mv^2}{r} \\\\F_g = \frac{GMm}{r^2} \\\\\frac{v^2}{r}  = \frac{GM}{r^2}\\\\v^2 = \frac{GM}{r} \\\\v^2 r = GM\\\\v_1^2 r _1 = v_2^2 r_2\\\\v_A^2r_A = v_B^2 r_B\\\\(\frac{v_A}{v_B} )^2 = \frac{r_B}{r_A} \\\\\frac{v_A}{v_B}  = \sqrt{\frac{r_B}{r_A} } \\\\\frac{v_A}{v_B}  = \sqrt{\frac{(800,000\  + \ 6.4 \times 10^6}{(500,000\  + \ 6.4 \times 10^6} )} \\\\\frac{v_A}{v_B}  =  1.02 \\\\v_A = 1.02 \ v_B

v_A = v_B( 100\% \ + 2\%)\\\\v_A = 100\%v_B \ + \ \ 2\% v_B\\\\v_A = v_B \ \ + \ 2\% v_B

Thus, the velocity of Satellite A is 2% greater than velocity of satellite B.

Learn more about velocity of satellite here: brainly.com/question/13981089

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