Answer:

Step-by-step explanation:
First problem. If you want a parallel to a given line, you keep the slope.
Then we use the point-slope form of a line
and we plug in there everything we need.

The second is quite similar. This time we want the perpendicular. It means that the product of the slopes has to be -1.

At this point we have everything, let's replace and write down the line in a better looking form

<em><u>Solution</u></em><em><u> </u></em><em><u>1</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
Statement : corresponding angles in similar triangles must be congruent .
Answer : True
<em><u>Solution</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
Statement : The hypotenuse of a right angle triangle has to be opposite of 90 degree .
Answer : True
Reason : We know that the side opposite to largest angle in a triangle is largest . Since in a right angle triangle 90 degree is the largest angle and hypotenuse is the longest side therefore they must be opposite to each other .
Answer:
-10
Step-by-step explanation:

step two is the rule of signs for multiplication
The value of x is 5. Thus, the correct statement is:
x = 5 is a true solution because log subscript 2 Baseline (16) = 4
<h3>Data obtained from the question </h3>
- Log₂ (x + 11) = 4
- Value of x =?
<h3>How to determine the value of x </h3>
Log₂ (x + 11) = 4
x + 11 = 2⁴
x + 11 = 16
Collect like terms
x = 16 – 11
x = 5
<h3>**Check** </h3>
Log₂ (x + 11) = 4
x = 5
Log₂ (5 + 11) = 4
Log₂ 16 = 4
Find the value of Log₂ 16
Log₂ 16 = n
16 = 2ⁿ
2⁴ = 2ⁿ
n = 4
Thus,
Log₂ 16 = 4
Therefore, the correct answer to the question is:
x = 5 is a true solution because log subscript 2 Baseline (16) = 4
Complete question
Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4. x + 11 = 2 Superscript 4. x + 11 = 16. x = 5. x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 2 x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 4 x = 5 is a true solution because log Subscript 2 Baseline (16) = 4 x = 5 is a true solution because log Subscript 4 Baseline (16) = 2
Learn more about Logarithm equation:
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