Answer:
Stoichiometric Coefficients
The balanced equation makes it possible to convert information about one reactant or product to quantitative data about another element. Understanding this is essential to solving stoichiometric problems
Explanation:
Calculate first the number of moles of ethylene glycol by dividing the mass by the molar mass.
n = (6.21 g ethylene glycol) / 62.1 g/mol
n = 0.1 mol
Then, calculate the molality by dividing the number of moles by the mass of water (in kg).
m = 0.1 mol/ (0.025 kg) = 4m
Then, use the equation,
Tb,f = Tb,i + (kb)(m)
Substituting the known values,
Tb,f = 100°C + (0.512°C.kg/mol)(4 mol/kg)
<em>Tb,f = 102.048°C</em>
Answer:
The molarity of the solution is 1.1 
Explanation:
Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in units
In this case
- number of moles of solute= 0.564 moles
- volume= 0.510 L
Replacing:
Solving:
molarity= 1.1
<u><em>The molarity of the solution is 1.1 </em></u><u><em></em></u>
Plant cells<span> are </span>eukaryotic cells<span>. Prokaryotic </span>cells<span> do not contain a membrane bound nucleus, mitochondria or other membrane bound </span>cell<span> structures (organelles), the DNA of prokaryotic </span>cells<span> are located in the cytoplasm of the </span>cell<span>. ... </span>Plant cells<span> are </span>eukaryotic<span> because they have a nuclear membrane.
so therefore, A rose thorn is a eukaryotic plant cell.</span>
Answer:
14.77 mol.
Explanation:
- It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.
<u><em>Using cross multiplication:</em></u>
1.0 mole of He contains → 6.022 x 10²³ atoms.
??? mole of He contains → 8.84 x 10²⁴ atoms.
<em>∴ The no. of moles of He contains (8.84 x 10²⁴ atoms) </em>= (1.0 mol)(8.84 x 10²⁴ atoms)/(6.022 x 10²³ atoms) =<em> 14.77 mol.</em>
