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Radda [10]
3 years ago
10

What is the mass of 7.91 cm to the power of three piece of lead having a density of 11.34 g/cm to the power of three?

Chemistry
1 answer:
miss Akunina [59]3 years ago
4 0

Hey there!

D = 11.34 g/cm³

V = 7.91 cm³

Therefore:

m = D * V

m = 11.34 * 7.91

m = 89.6994 g

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Create a comic strip that follows the journey of energy from the sun as it travels through the humpback whale
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The path of energy flow from the sun to the humpback whale is as follows:

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<h3>What is energy?</h3>

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The primary source of energy on the earth is the sun.

The energy from the sun is used by producers to produce food on which other organisms depend on.

The energy from the sun gets to the humpback whale through producers such as plankton.

The path of energy flow from the sun to the humpback whale is as follows:

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4 0
2 years ago
Carbon, hydrogen and ethane each burn exothermically in an excess of air. AHⓇ =-393.7 kJ mol. C(s) + O2(g) → CO2(g) H2(g) + % O2
Salsk061 [2.6K]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 51.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of carbon and water follows:

2C(s)+2H_2(g)\rightarrow C_2H_4(g) \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_1=-393.7kJ    ( × 2)

(2) H_2+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_2=-285.9kJ     ( × 2)

(3) 2C_2H_4(s)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)    \Delta H_3=-1411kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[2\times \Delta H_1]+[2\times \Delta H_2]+[1\times (-\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times (-393.7))+(2\times (-285.9))+(1\times -(-1411))]=51.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is 51.8 kJ.

6 0
3 years ago
The addition of phosphate to a chemical compound is called A. glycolysis. B. oxidation. C. reduction. D. phosphorylation.
stich3 [128]

Answer:

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When these electrons change orbit or level they release energy in the form of light, which is known as a photon.

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