Which of the following would double the pressure on a contained gas at constant temperature?
1 answer:
Answer: C. doubling the number of particles in the container
Explanation: According to the ideal gas equation:'
P= Pressure of the gas
V= Volume of the gas
n= number of moles
T= Temperature of the gas
R = gas constant
As the gas is contained in a container with fixed volume and temperature is also constant.
Therefore, the pressure will double when number of moles or number of particles double.
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Answer:
Diagram 1
Explanation:
The solubility of the oxygen gas in water has to do with the interaction of the oxygen with the dipoles in water.
Water is a polar molecule having oxygen as the negative dipole and hydrogen as the positive dipole.
Water can interact with the oxygen atoms in the molecule via intermolecular hydrogen bonds with molecular oxygen as shown in diagram 1.
Answer : The percent by mass of the solution is 7.81 %
Explanation : Given,
Mass of NaCl = 8.75 g
Mass of solution = 112.0 g
Now we have to determine the percent by mass of the solution.
Putting values in above equation, we get:
Therefore, the percent by mass of the solution is 7.81 %