Answer:
8 years
Step-by-step explanation:
Tim's account balance has an initial value of $6400 and is multiplied yearly by the factor 1.01. Thus, it can be described by the exponential equation ...
b = 6400·1.01^t
where b is the balance after t years.
Putting in the desired balance, we can find t.
6900 = 6400·1.01^t
1.078125 = 1.01^t . . . . . divide by 6400
log(1.078125) = t·log(1.01) . . . . take the logarithm of both sides
log(1.078125)/log(1.01) = t ≈ 7.56 ≈ 8 . . . . . divide by the coefficient of t
It will take Tim approximately 8 years to reach a balance of $6900.
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The problem can also be solved using a graphing calculator.
Answer:
(x-1)²/49 + (y+3)²/16.51 = 1
Step-by-step explanation:
vertex (8,-3) Foci (6.7,-3) center (h,k) = (1,-3) , major axis parallel to x axis
a is the distance of the vertex from the center, and c is the distance of the foci from the center. b is semi-minor axis
b² = a² - c² Ellipse equation: (x-h)²/a² + (y-k)²/b² = 1
a = 8-1 = 7 c = 6.7 - 1 = 5.7
b² = 7² - 5.7² = 16.51
Ellipse equation: (x-1)²/49 + (y- -3)²/16.51 = 1 i.e. (x-1)²/49 + (y+3)²/16.51 = 1
Maurice wants to create a set of elliptical flower beds. To do this, he first plots the location of the two fruit trees on his graph.
Maurice has to use the equation a^2-b^2=c^2. We know that c=3, and because we need 1 more number to solve for b, I made a=6. 6^2-b^2=3^2. 36-b^2=9. b^2=27. b=5.196
<span>Next, to create the equation, we substitute what we know into the equation x^2/a^2 + y^2/b^2=1 and get x^2/36 + y^2/27=1. Johanna wants to create some hyperbolic flower beds.
We already know that c=3 so this time I decided a=1. 3^2=1^2+b^2. 9=1+b^2. 8=b^2. b=2.828
Next, to create the equation, we substitute what we know to the equation x^2/a^2 - y^2/b^2 = 1. x^2/1^2 - y^2/2.828^2 = 1. </span>
Your answer is -4. Good Luck!
Name me brainliest answer please!
Answer:
a) a to the power of 2
b) c
Step-by-step explanation:
