Answer:
7x[∛x^2y]
Step-by-step explanation:
given:
![5x\sqrt[3]{x^2y} +2\sqrt[3]{x^5y} \\5x(x^\frac{2}{3}.y^\frac{1}{3}) + 2.x^\frac{5}{3}.y^\frac{1}{3} \\5x.x^\frac{2}{3}.y^\frac{1}{3} + 2.x^\frac{5}{3}.y^\frac{1}{3} \\5x^\frac{5}{3}.y^\frac{1}{3} + 2.x^\frac{5}{3}.y^\frac{1}{3} \\\\ y^\frac{1}{3} (5x^\frac{5}{3} + 2x^\frac{5}{3} )\\y^\frac{1}{3} (7x^\frac{5}{3}} )\\7\sqrt[3]{x^5y}\\ 7x\sqrt[3]{x^2y}](https://tex.z-dn.net/?f=5x%5Csqrt%5B3%5D%7Bx%5E2y%7D%20%2B2%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%5C%5C5x%28x%5E%5Cfrac%7B2%7D%7B3%7D.y%5E%5Cfrac%7B1%7D%7B3%7D%29%20%2B%202.x%5E%5Cfrac%7B5%7D%7B3%7D.y%5E%5Cfrac%7B1%7D%7B3%7D%20%20%20%20%5C%5C5x.x%5E%5Cfrac%7B2%7D%7B3%7D.y%5E%5Cfrac%7B1%7D%7B3%7D%20%2B%202.x%5E%5Cfrac%7B5%7D%7B3%7D.y%5E%5Cfrac%7B1%7D%7B3%7D%20%5C%5C5x%5E%5Cfrac%7B5%7D%7B3%7D.y%5E%5Cfrac%7B1%7D%7B3%7D%20%2B%202.x%5E%5Cfrac%7B5%7D%7B3%7D.y%5E%5Cfrac%7B1%7D%7B3%7D%20%5C%5C%5C%5C%20%20y%5E%5Cfrac%7B1%7D%7B3%7D%20%285x%5E%5Cfrac%7B5%7D%7B3%7D%20%2B%202x%5E%5Cfrac%7B5%7D%7B3%7D%20%29%5C%5Cy%5E%5Cfrac%7B1%7D%7B3%7D%20%287x%5E%5Cfrac%7B5%7D%7B3%7D%7D%20%29%5C%5C7%5Csqrt%5B3%5D%7Bx%5E5y%7D%5C%5C%207x%5Csqrt%5B3%5D%7Bx%5E2y%7D)
!
The answer is: " 3 " .
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Explanation:
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(3/4) ÷ (1/4) = (3/4) * (4/1) = ?
The "4's" cancel out to "1's" ; → {since: "4 ÷ 4 = 1 " } ;
And we can rewrite the expression as:
" (3/1) * (1/1) " ;
→ " (3/1) * (1/1) = 3 * 1 = " 3 " .
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The answer is: " 3 " .
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Answer:
264/7 37.71
Step-by-step explanation:
22/7×6(2)
=>22/7×12
=>37.71 or 264/7
D (38.63) because it wouldn’t make sense if the number was less than 10 when the line is clearly longer
There are standard formulas for this type of problem. However, it can also be solved by a combination of simple steps.
First, the shortest distance from the point (3,5) to the line y = x +4 (line1) will be along a straight line perpendicular to line1. Give the perpendicular line the name line2. Since the slope of line1 is 1, the slope of line2 will be -1.
Second, since line2 must go through (3,5) and also have a slope of -1, the point slope form can be used for line2:
y - 5 = (-1) (x -3)
So the equation of line2 is y = -x +8.
Third, the point of intersection of line1 and line2 can be found by solving the set of equations:
y = x +4
y = -x + 8
The solution of this set of two equations is x = 2, y = 6 i.e. the point (2,6) .
Fourth, the distance formula can be used to find the distance between (3,5) and (2,6)
d = sqrt( (3-2)2 + (5-6)2 ) = sqrt(2)
This is the desired distance.
