Please helpppp meee outttt

using the graph,find the value of the constant in the equation below.if necessary,round your answer to the nearest integer (Pict

Ugo [173]

The equation is the form:
Height = Constant / Width

There are several points that can be used to determine the constant. Picking out one which is (4,20)
20 = Constant / 4
Constant = 4(20)
Constant = 80

The constant is 80.

3 0

2 years ago

Read 2 more answers

The graph shows a probability distribution. What is P(X<5)

Thepotemich [5.8K]

Answer:

P(x < 5) = 0.70

Step-by-step explanation:

Note: The area under a probability "curve" must be = to 1.

Finding the sub-area representing x < 5 immediately yields the desired probability.

Draw a dashed, vertical line through x = 5. The resulting area, on the left, is a trapezoid. The area of a trapezoid is equal to:

(average length)·(width, which here is:

2 + 5

----------- · 0.02 = (7/2)(0.2) = 0.70

2

Thus, P(x < 5) = 0.70

7 0

2 years ago

Solve x2 – 3x - 108 = 0.

rewona [7]

X=12, -9 I hope this somewhat helps you :)

7 0

3 years ago

An air conditioning system can circulate 320 cubic feet of air per minute. How many cubic yards of air can it circulate per minu

Agata [3.3K]

Step-by-step explanation:

It is given that, an air conditioning system can circulate 320 cubic feet of air per minute. We need to find how many cubic yards of air can it circulate per minute?

1 yard = 3 foot

1 feet = (1/3) yard

320 feet = 106.66 yard

$320\ \text{feet}^3=320\times( \dfrac{1}{3})^3\ \text{yard}^3\\\\=11.85\ \text{yard}^3$

So, it will circulate 11.85 cubic yard of air per minute.

5 0

2 years ago

A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the

Kay [80]

Answer: The required number of quarters in the collection is 11.

Step-by-step explanation: Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05, 1 dime = $ 0.10 and 1 quarter = $0.25.

Then, according to the given information, we have

$x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

$(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)$

and

$y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Comparing the values of y from equations (iv) and (v), we get

$47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.$

Thus, the required number of quarters in the collection is 11.

7 0

2 years ago