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Zigmanuir [339]
2 years ago
15

Please helpppp meee outttt

Mathematics
1 answer:
Elan Coil [88]2 years ago
3 0

Answer:

Measure of <z would 125 degrees

Step-by-step explanation:

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. Find two consecutive odd integers whose product is 99. (Note: There are two different pairs of consecutive odd
Tom [10]

Answer:

9 and 11

Step-by-step explanation:Let the 2 consecutive odd integers be n and n+2.

n(n + 2) = 99

Solve for n.

n2 + 2n - 99 = 0

(n + 11)(n - 9) = 0 ⇒

Two solutions:

n = -11

n + 2 = -9

and

n = 9

n + 2 = 11

Test the answers.

4 0
3 years ago
Help me a soon as possible I need your help help help please as soon as possible ASAP
evablogger [386]

Answer:

B

Step-by-step explanation:

The answer is b because the lines outside -65 are symbols for absolute value. Absolute value means the distance away from 0, so b would be an appropriate choice.

5 0
3 years ago
Read 2 more answers
???????????????????help
Simora [160]

Answer: 10

Step-by-step explanation:

add 2.75 to 0

4 0
3 years ago
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POSSIBLE POINTS: 5
Bumek [7]

Answer:

176/231

Step-by-step explanation:

88 blue marbles, 55 green marbles, and 88 red marbles =231 marbles

P (blue or red marble) = number of red or blue/ total

                                     = 88+88 / 231

                                      =176/231

4 0
3 years ago
a math teacher claims that she has developed a review course that increases the score of students on the math portion of a colle
madam [21]

Answer:

A.

H_0: \mu\leq514\\\\H_1: \mu>514

B. Z=2.255. P=0.01207.

C. Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. P(z>0.94)=0.1736

Step-by-step explanation:

<em>A. state the null and alternative hypotheses.</em>

The null hypothesis states that the review course has no effect, so the scores are still the same. The alternative hypothesis states that the review course increase the score.

H_0: \mu\leq514\\\\H_1: \mu>514

B. test the hypothesis at the a=.10 level of confidence. is a mean math score of 520 significantly higher than 514? find the test statistic, find P-value. is the sample statistic significantly higher?

The test statistic Z can be calculated as

Z=\frac{M-\mu}{s/\sqrt{N}} =\frac{520-514}{119/\sqrt{2000}}=\frac{6}{2.661}=2.255

The P-value of z=2.255 is P=0.01207.

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

Then we can conclude that the score of 520 is significantly higher than 514, in this case, specially because the big sample size.

C.​ do you think that a mean math score of 520 vs 514 will affect the decision of a school admissions adminstrator? in other words does the increase in the score have any practical significance?

Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. test the hypothesis at the a=.10 level of confidence with n=350 students. assume that the sample mean is still 520 and the sample standard deviation is still 119. is a sample mean of 520 significantly more than 514? find test statistic, find p value, is the sample mean statisically significantly higher? what do you conclude about the impact of large samples on the p-value?

In this case, the z-value is

Z=\frac{520-514}{s/\sqrt{n}} =\frac{6}{119/\sqrt{350}} =\frac{6}{6.36} =0.94\\\\P(z>0.94)=0.1736>\alpha

In this case, the P-value is greater than the significance level, so there is no evidence that the review course is increasing the scores.

The sample size gives robustness to the results of the sample. A large sample is more representative of the population than a smaller sample. A little difference, as 520 from 514, but in a big sample leads to a more strong evidence of a change in the mean score.

Large samples give more extreme values of z, so P-values that are smaller and therefore tend to be smaller than the significance level.

8 0
3 years ago
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