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madreJ [45]
3 years ago
9

Create a sequence with a pattern rule of "add ." Sequence terms Create a sequence with a pattern rule of "multiply by ." Sequenc

e terms Create a sequence with a pattern rule of "add subtract ." Sequence terms Create a sequence with a pattern rule of "multiply by , divide by ." Sequence terms Create a sequence with your own rule Sequence terms. Someone please help me this was due in october
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Firstly, to create a sequence we need our natural numbers which will stand for our n and the pattern created will be f(n). where n = 1, 2, 3, 4, . . .

1. If we have f(n) = n + 1, then our sequence would be 2, 4, 5, 6, . . .  with a pattern of adding 1 to our n.

2. If we have f(n) = n x 2, then our sequence would be 1, 4, 6, 8, . . .  with a pattern of multiplying 2 by our n.

3.  If we have f(n) = n + 2 when n is odd and n - 1 when even, then we have 3, 1, 5, 3, . . . as our sequence following the add subtraction pattern.

4. if we have f(n) = n x 2 when n is odd and n/1 when n is even, then we have 2, 4, 10, 6, . . .

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Coefficient of b in expansion of (3+b)^4
Margarita [4]
Are you sure you want ONLY the coefficient of b?  If you expand this, you will have b in 3 of 4 terms.

According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:

                             1
                        1    2    1
                   1      3    3     1
              1       4     6     4     1

So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4

Here, you want (3 + b)^4.  Here's what that looks like:

3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]

Which coeff did you want?
4 0
3 years ago
1. Write 6 x 104 in standard form. <br> O 600 <br>O 6,000 <br>O 60.000<br> O 600.000​
BlackZzzverrR [31]

the answer is 60,000

For Connexus students:

1.  6,0000

2. 2,300

3. 9.68 x 10 to the 5th power

4. 8.6 x 10 to the 3rd power

5. the number of places to move the decimal point to the right

6 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
1. Write the equation c = loga(b) in exponential form.
Flauer [41]

Answer:

Step-by-step explanRemember: logax=b⇒ab=x

in which "a" is the base of the log. 

log4 (1/16) = 4^-2 = 1/4^2 = 1/16

4 to the power of -2 is equal to 1/16.

To answer this question, the equation in exponential form of "log4 (1/16) = -2" is " 4^-2 " (4 to the power of -2). :D

plz mark me brainliest

7 0
3 years ago
Solve 3(x + 1) + 6 = 33.
sammy [17]

add 6 plus 33 then do x+1 then you divide

Step-by-step explanation:

7 0
3 years ago
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