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cricket20 [7]
2 years ago
5

What is the definition of bond (in chemistry) ?

Chemistry
2 answers:
jeka942 years ago
8 0

Answer:

Bond is a force that binds two atoms together.

Sav [38]2 years ago
5 0

Answer:

A bond is a link between atoms in molecules or compounds and between ions and molecules in crystals. A bond represents a lasting attraction between different atoms, molecules or ions.

Hope this helps!

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Ammonia (nh3) is widely used as a fertilizer and in many household cleaners. how much ammonia is produced when 6.64 mol of hydro
olga55 [171]
N₂ + 3H₂ ⇒ 2NH₃

doesnt matterN₂ + 6.64H₂ ⇒ 2NH₃

(6.64H₂/3H₂) x (2NH₃) =4.4266667

rounded to sig figs= 4.43

5 0
3 years ago
You are requested to reduce the size of 50 ton/hr of a given solid. The size of the feed is such 80% passes a 4-in (76.2 mm) scr
defon

Answer:

1) The power needed to process 50 ton/hr is 135.4 HP.

2) The void fraction of the bed is 0.37.

Explanation:

1) For this type of milling operations, we can estimate the power needed for an operation according to the work index (Ei), the passing size of the circuit feed (F80) and the passing size of the product (P80).

We assume the units of Ei are kWh/t.

The equation that relates this parameters and the power is (size of particles in μm):

W=Ei*(\frac{10}{\sqrt{P80}} -\frac{10}{\sqrt{F80}} )\\\\W=9.45*(\frac{10}{\sqrt{3175\mu m}} -\frac{10}{\sqrt{76200mm}} )\\\\\\W=9.45*(0.1774+0.0362)=2.019 kWh/t

The power needed to process 50 ton/hor is

P=2.0194\frac{kWh}{Ton}*\frac{50Ton}{h}*\frac{1.341HP}{1kW}=   135.4 \, HP

2) The density of the packed bed can be expressed as

\rho=f_v*\rho_v+f_s*\rho_s

being f the fraction and ρ the density of every fraction. We know that the density of the void is 0 (ρv=0) and that fv=1-fs (the sum  of the fractions ois equal to the total space).

Then we can rearrange

\rho=f_v*\rho_v+f_s*\rho_s\\\\\rho=f_v*0+(1-f_v)*\rho_s\\\\\rho/\rho_s=1-f_v\\\\f_v=1-\rho/\rho_s=1-990/1570=1-0.63=0.37

The void fraction of the bed is 0.37.

6 0
3 years ago
Given the name select the correct formula for each ion compound
MariettaO [177]

Please provide more info

4 0
3 years ago
How many moles of aluminum are needed to react with 3.6 mol of FeO? 2Al(s) + 3FeO(s) ----> 3Fe(s) + Al^2O^3(s)
kupik [55]
3.6 mol (2 Al/3 FeO)=2.4 mol
6 0
3 years ago
A 13.97 g sample of nabr contains 22.34% na by mass. Considering the law of constant composition (definite proportions) how many
Grace [21]

As per the law of constant composition, a given sample will always contain the same number of elements that combine in the same mass proportion.

Therefore if a sample of 13.97 g of NaBr contains 22.39 % of Na by mass then,  a sample of 5.75 g of NaBr would also contain 22.39% Na by mass

Hence:

Mass of Na = 5.75 g * 22.39/100 = 1.287 g

5.75 g of NaBr would contain 1.29 g of Na

3 0
3 years ago
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