Answer:
2.95 * 10^23 atoms
Explanation:
The number of atoms in a mole is always equal to <u>Avogadro's constant</u>, which is <u>6.02214076×10²³ mol⁻¹</u>.
To find the number of atoms in 0.490 moles of barium, multiply it with <u>Avogadro's constant</u>:
0.490 mol * 6.02214076×10²³ mol⁻¹ ≈ 2.9508 * 10^23
Convert to SigFigs (if necessary):
2.95 * 10^23
Answer:
The answer to the question is
The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.
Explanation:
To solve the question, we write out the chemical equation as follows
NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)
From the above equation, it is observed that only the gaseous products contribute to the partial pressure
Kp =PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases
However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S
Then PNH₃ = √(0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.
Okay cool! thats not enough detail though
Answer:
b) [Kr] 5s² 4d¹⁰ 5p⁵
Explanation:
Properties of iodine:
Iodine is present in group seventeen.
It is halogen element.
Its atomic mass is 127 amu.
Its atomic number is 53.
It is present in solid form.
It is crystalline in nature.
It is very corrosive and has pungent odor.
It can not react with oxygen and nitrogen.
Electronic configuration:
I₅₅ = 1s² 2s² 2p⁶ 3s³ 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration:
I₅₅ = [Kr] 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration is shortest electronic configuration by using the noble gases.
