Answer:
London dispersion
Explanation:
I got the question right (;
The amount of N2O5 to start with would be 35.79 grams
<h3>Stoichiometric calculations</h3>
From the balanced equation of the reactions:
Mole ratio of N2O5 and NO2 = 1:2
Since the reaction's actual yield is 82%, the theoretical yield would be: 25 x 100/82 = 30.49 grams
Mole of 25 g NO2 = 30.49/46
= 0.66 mole
Equivalent mole of N2O5 = 0.54/2 mole
= 0.33 moles
Mass of 0.27 mole N2O5 = 0.33 x 108.01
= 35.79 grams
More on stoichiometric calculations can be found here: brainly.com/question/8062886
Answer: The vapor pressure of the solution at is 137 torr
Explanation:
As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.
The formula for relative lowering of vapor pressure will be,
where,
= relative lowering in vapor pressure
i = Van'T Hoff factor = 1 (for non electrolytes)
= mole fraction of solute =
Given : 13.06 g of napthalene is present in 100 g of solution, thus (100-13.06) g = 86.94 g of hexane
moles of solute (napthalene) =
moles of solvent (hexane) =
Total moles = moles of solute (napthalene) + moles of solvent (hexane) = 0.102 + 1.01 = 1.112
= mole fraction of solute (napthalene) =
Thus the vapor pressure of the solution at is 137 torr