Complete dominance.... Hope this helps
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Answer:
Percent yield of SiC is 77.0%.
Explanation:
Balanced reaction: 
Molar mass of SiC = 40.11 g/mol
Molar mass of
= 60.08 g/mol
So, 100.0 kg of
=
moles of
= 1664 moles of 
According to balanced equation, 1 mol of
produces 1 mol of SiC
Therefore, 1664 moles of
produce 1664 moles of SiC
Mass of 1664 moles of SiC =
= 66743g = 66.74 kg (4 sig. fig.)
Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]
%
=
%
= 77.0%