San had a banner that is made of a square and a semicircle. The square has side lenghts of 10 inches. One side of the square is
1 answer:
You might be interested in
Answer:
The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.
Step-by-step explanation:
We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have
And apply it to get the horizontal and vertical displacements.
Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.
Linear displacements.
Using the definition of displacement, we can write the horizontal displacement as
So we can use the given points on the displacement formula
In the same manner we can look at the y components of those points to find the vertical displacement
Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.
Projection angle.
The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write
Solving for the angle we get
Replacing values
Which give us
So the projection angle is 39.3 degrees.
Answer:
The answer to your questions is below
Step-by-step explanation:
4.-
In a 45°-45°-90° triangle, the length of the legs are "x" and the length of the hypotenuse is x
Then, in this problem, the length of the leg is 7 then the length of the hypotenuse will be 7
5.- In a 30°-60°-90° triangle, the length of the hypotenuse is 2x, the length of the longer leg is x and the length of the shorter leg is x.
In this problem we have the length of the hypotenuse = 20 and find x.
2x = 20
x = 20/2
x = 10
longer leg = x
6.- nonzero
7.- hypotenuse = 20 cm
Find x
2x = 20
x = 20/2
x = 10
Shoter leg = x = 10 cm