Hi! My responsibility is to add and protection to plant cells. what i am

Need help on both questions. Only if you know.

Aleks04 [339]

B, a. hopefully that helps

4 0

3 years ago

Question 15 (5 points)

Vladimir [108]

This problem is providing us with the maximum mass of Imitrex a patient can get daily as 0.2 g. Also, the mass of a tablet is given as 25 mg so the number of tablets they get in a day is required. After the calculations, the result turns out to be 10 tablets.

<h3>Dimensional analysis:</h3>

In chemistry, dimensional analysis is used to calculate specific outcomes given useful information to do so. Despite not having specific formulas for every problem, one can come up with a feasible proportional-factor-based setup, in order to obtain the required.

In this case, since the mass per tablet is 25 mg, one can divide the maximum dosage by this mass per tablet, both in grams, to obtain the required number of tablets for a daily dosage:

$25\frac{mg}{tablet}*\frac{1g}{1000mg}=0.025\frac{g}{tablet} \\\\\#tablets=\frac{0.25g}{0.025\frac{g}{tablet}} \\\\\#tablets=10 tablets$

Learn more about dimensional analysis: brainly.com/question/10874167

6 0

2 years ago

A buffer solution is prepared by placing 5.86 grams of sodium nitrite and 32.6 mL of a 4.90 M nitrous acid solution into a 500.0

N76 [4]

This question is incomplete, the complete question is;

A buffer solution is prepared by placing 5.86 grams of sodium nitrite and 32.6 mL of a 4.90 M nitrous acid solution into a 500.0 mL volumetric flask and diluting to the calibration mark. If 10.97 mL of a 1.63 M solution of potassium hydroxide is added to the buffer, what is the final pH? The Ka for nitrous acid = 4.6 × 10⁻⁴.

Answer:

the final pH is 3.187

Explanation:

Given the data in the question;

Initial moles of HNO2 = 32.6/1000 × 4.90 = 0.15974 mol

Initial moles of NO2- = mass/molar mass = 5.86/68.995 = 0.0849336 mol

Moles of KOH added = 10.97/1000 × 1.63 = 0.0178811 mol

so

HN02 + KOH → NO2- + H2O

moles of HNO2 = 0.15974 - 0.0178811 = 0.1418589 mol

Moles of NO2- = 0.0849336 + 0.0178811 = 0.1028147 mol

Now,

pH = pka + log( [NO2-]/[HNO2])

pH = -log ka + log( moles of NO2- / moles of HNO2 )

we substitute

pH = -log( 4.6 × 10⁻⁴ ) + log( 0.1028147 / 0.1418589 )

pH = -log( 4.6 × 10⁻⁴ ) + log( 0.724767 )

pH = 3.337242 + (-0.1398 )

pH = 3.187

Therefore, the final pH is 3.187

8 0

3 years ago

Someone help answer this

alexandr402 [8]

it is water energy :) this is easy

6 0

3 years ago

Read 2 more answers

PLEASE HELP!! What happens when nitrogen fills its valence shell?

Sidana [21]

I think the answer is that three electrons are gained, creating N-3

5 0

3 years ago

Read 2 more answers

Hi! My responsibility is to add and protection to plant cells. what i am​

Hi! My responsibility is to add and protection to plant cells. what i am