We have get the mass of gaseous water after evaporation in a closed container.
The mass of water vapor after evaporation is 5 grams.
In closed container, there is no exchange in mass from system to surrounding, only heat may exchange. The number of moles of water vapour remains unchanged as 5 gram water is heated in closed container.
Due to heating, liquid water gets evaporated and intermolecular distance between water molecules increases in gaseous state than liquid state and intermolecuar force of attraction decreases.
Randomness of molecules increases in gaseous state than liquid state.
HCl = H⁺ + Cl⁻
c(HCl)=9.8*10⁻⁵ mol/l
pH=-lg[H⁺]
[H⁺]=c(HCl)
pH=-lg{c(HCl)}
pH=-lg{9.8*10⁻⁵}=4.009
pH=4.009
Answer:
16.5moles of CO2
Explanation:
Molar mass of O2 is 32g/Mol
No of mole = 880/32 = 27.5 moles
27.5 Mol of O2 gives X mole of CO2
5 mole of O2 gives 3 moles of CO2
No of mole of CO2 = (27.5×3)/ 5 = 16.5moles
The number of moles of 210 grams of NaHCO₃ is 2.5 moles.
<h3>How to find the Number of moles ? </h3>
To calculate the number of moles use the formula
Number of moles = 
Mass of NaHCO₃ = 210 g
Now we have to find the Molar mass of NaHCO₃
= Atomic mass of Na + Atomic mass of H + Atomic mass of C + 3 (Atomic mass of O)
= 23 + 1 + 12 + 3 (16)
= 36 + 48
= 84 g/mol
Now put the value in above formula we get
Number of moles =
= 
= 2.5 moles
Thus from the above conclusion we can say that The number of moles of 210 grams of NaHCO₃ is 2.5 moles.
Learn more about the Moles here: brainly.com/question/15356425
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