The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.
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Magnitude of magnetic force on the proton</h3>
The magnitude of magnitude force on the proton is calculated as follows;
F = qvB sinθ
where;
- q is the charge of the proton
- v is the speed of the proton
- B is the magnitude of the magnetic filed
- θ is the angle between the field and speed
Substitute the given parameters and solve for the magnetic force.
F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)
F = 2.4 x 10⁻¹² N
Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.
Learn more about magnetic force here: brainly.com/question/13277365
Pendulum under goes energy conversions from potential to kinetic and back to potential.
A pendulum consists of a long string to which a bulb is attached. The string is fastened to a point from which it can oscillate freely when displaced through a small angle.
The pendulum is an example of a system in which energy conversion takes place. The energy is converted from potential to kinetic and back to potential. Since the image was not shown in the question, we can not locate the specific points where the energy conversions occur.
Learn more: brainly.com/question/14759840
Explanation:
r^2= 9×10^9 × 5.87×5.87×10^-16 / 64.9
=47.7× 10^-8
so taking sq. root
r = 6.9 ×10^-4 m
or
r= 6.9×10^ -2 cm
this gives the required seperation
Answer : The correct option is, (d) 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of copper = 
= specific heat of water = 
= mass of copper = 120 g
= mass of water = 300 g
= final temperature of mixture = 
= initial temperature of copper = ?
= initial temperature of water = 
Now put all the given values in the above formula, we get:
Therefore, the temperature of the kiln was,
Answer:
a) v = 1.075*10^7 m/s
b) FB = 7.57*10^-12 N
c) r = 10.1 cm
Explanation:
(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:
(1)
q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C
V: potential difference = 1.2*10^6 V
You replace the values of the parameters in the equation (1):
The kinetic energy of the particle is also:
(2)
m: mass of the particle = 6.64*10^⁻27 kg
You solve the last equation for v:
the sped of the alpha particle is 1.075*10^6 m/s
b) The magnetic force on the particle is given by:
B: magnitude of the magnetic field = 2.2 T
The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1
the force exerted by the magnetic field on the particle is 7.57*10^-12 N
c) The particle describes a circumference with a radius given by:
the radius of the trajectory of the electron is 10.1 cm
