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3 years ago

A 0.15 kg baseball is pushed with 100 N force. what will its acceleration be?

Physics

1 answer:

sammy [17]3 years ago

8 0

Answer:

The acceleration of the ball is 666.67 m/s²

Explanation:

It is given that,

Mass of the baseball, m = 0.15 kg

Applied force to it, F = 100 N

We need to find the acceleration of the ball. It can be calculated using Newton's second law of motion as :

F = ma

$a=\dfrac{F}{m}$

$a=\dfrac{100\ N}{0.15\ kg}$

$a=666.67\ m/s^2$

So, the acceleration of the ball is 666.67 m/s². Hence, this is the required solution.

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An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s). If a particular disk is spun at 646.

lesya692 [45]

Answer:

Angular acceleration will be $1135.5rad/sec^2$

Explanation:

We have given initial angular speed of a particular disk $\omega _i=646.1rad/sec$

And it finally comes to rest so final angular speed $\omega _f=0rad/sec$

Time is given as t = 0.569 sec

From third equation of motion we know that

$\omega _f=\omega _i+\alpha t$

So angular acceleration $\alpha =\frac{\omega _f-\omega _i}{t}=\frac{0-646.1}{0.569}=1135.5rad/sec^2$

3 0

3 years ago

Question is in the picture

elena-14-01-66 [18.8K]

Answer: Imma say 63 cm

7 0

2 years ago

Read 2 more answers

What is the maximum distance that a 60.-watt motor may vertically lift a 90.-newton?weight in 7.5 seconds?a. 2.3mb. 5.0mc. 140md

Naddik [55]

Answer:

b. 5.0 m

Explanation:

Power: Power can be defined as the rate at which work is done.

The S.I unit of power is watt (W).

P = W/t ............................................... Equation 1

Where p = power, W = work, t = time.

But

W = F×d..................................... Equation 2

Where F = force, d = maximum distance.

Substituting equation 2 into equation 1

P = F×d/t

making d the subject of the equation above,

d = Pt/F......................................................... Equation 3

Given: F = 90 Newton, P = 60 watt, t = 7.5 seconds.

Substituting these values into equation 3,

d = 60×7.5/90

d = 5 m

Thus the maximum distance is = 5 m

The right option is b. 5.0 m

5 0

3 years ago

A wheel is rotating at 30.0 rpm. The wheel then accelerates uniformly to 50.0 rpm in 10.0 seconds. Determine the – a) rate of an

Mademuasel [1]

Answer:

The angular acceleration is $0.209\ rad/s^2$

Explanation:

Given that,

Angular velocity, $\omega_{i} = 30.0\ rpm$

Angular velocity, $\omega_{f} = 50.0\ rpm$

Time t = 10.0 sec

We need to calculate the angular acceleration

Using formula of angular acceleration

$\alpha=\dfrac{\Delta \omega}{\Delta t}$

$\alpha=\dfrac{\omega_{f}-\omega_{i}}{\Delta t}$

$\alpha=\dfrac{50.0-30.0}{10.0}$

Now, we change the angular velocity in rad/s.

$\omega=20\times\dfrac{2\pi}{60}$

$\omega=2.09\ rad/s$

$\alpha=\dfrac{2.09}{10.0}$

$\alpha=0.209\ rad/s^2$

Hence, The angular acceleration is $0.209\ rad/s^2$

5 0

3 years ago

Read 2 more answers

A coin released at rest from the top of a tower hits the ground after falling 1.5 s. What is the speed of the coin as it hits th

Inessa05 [86]

initially coin is at rest and then it drop for total time t = 1.5 s

so here the speed of the coin at which it will hit the floor is to be find

$v_f = v_i + at$

here we know that

$v_i = 0$

a = 9.8 m/s^2

t = 1.5 s

now from above equation

$v_f = 0 + 1.5 (9.8)$

$v_f = 14.7 m/s$

so it will hit the floor with speed 14.7 m/s

3 0

3 years ago