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3 years ago

A 0.15 kg baseball is pushed with 100 N force. what will its acceleration be?

Physics

1 answer:

sammy [17]3 years ago

8 0

Answer:

The acceleration of the ball is 666.67 m/s²

Explanation:

It is given that,

Mass of the baseball, m = 0.15 kg

Applied force to it, F = 100 N

We need to find the acceleration of the ball. It can be calculated using Newton's second law of motion as :

F = ma

$a=\dfrac{F}{m}$

$a=\dfrac{100\ N}{0.15\ kg}$

$a=666.67\ m/s^2$

So, the acceleration of the ball is 666.67 m/s². Hence, this is the required solution.

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?a wire is stretched 30% what is the percentage change in resistance

Marat540 [252]

Answer:

The percentage change in resistance of the wire is 69%.

Explanation:

Resistance of a wire can be determined by,

R = (ρl) ÷ A

Where R is its resistance, l is the length of the wire, A its cross sectional area and ρ its resistivity.

When the wire is stretched, its length and area changes but its volume and resistivity remains constant.

$l_{o}$ = 1.3l, and $A_{o}$ = $\frac{A}{1.3}$

So that;

$R_{o}$ = (ρ $l_{o}$ ) ÷ $A_{o}$ = (ρ × 1.3l) ÷ ( $\frac{A}{1.3}$ )

= (1.3lρ) ÷ ( $\frac{A}{1.3}$ )

= $(1.3)^{2}$ × [(ρl) ÷ A]

= 1.69R (∵ R = (ρl) ÷ A)

$R_{o}$ = 1.69R

Where $R_{o}$ is the new resistance, $l_{o}$ is the new length, and $A_{o}$ is the new area after stretching the wire.

The change in resistance of the wire = $R_{o}$ - R

= 1.69R - 1R

= 0.69R

The percentage change in resistance = $\frac{0.69R}{R}$ × 100

= 0.69 × 100

= 69%

The percentage change in resistance of the wire is 69%.

3 0

3 years ago

Which of the following best describes seamounts and islands of the deep ocean basins?

Rina8888 [55]

Answer: The correct option is (d)

lava flows built up from the ocean floor by multiple, summit and flank eruptions

Explanation:

Piles of baseltic lava flows built up from the ocean floor by multiple summit and flank eruptions describes seamounts and islands of the deep ocean basins.

4 0

4 years ago

4. Two straight wires are parallel and carry currents of 1.2 A in opposite directions, as shown. Find the direction of the magne

Mariana [72]

The directions of magnetic force and magnetic field lines are shown in the figure.

The direction to find out the magnetic field lines is given by right hand curl rule. If the thumb shows the direction of current, then the curling fingers show the direction of magnetic field lines.

The direction of force can be given by right hand thumb rule, where

Thumb - Direction of magnetic field lines
Forefinger - Magnetic force
Centre finger - Current

Such that forefinger, centre finger and thumb must be at 90 degrees to each other.

6 0

3 years ago

What is the equivalent capacitance of the three capacitors in the figure (figure 1)?

vekshin1

The equivalent capacitance of the combination is $\dfrac{1}{C} = \dfrac{1}{C_1}+\dfrac{1}{C_2}$ where C1 and C2 are the capacitance of both capacitors in series.

<h3>What is equivalent capacitor?</h3>

Let the capacitance of both capacitors be C1 and C2. For a series connected capacitors, same charge flows through the capacitors but different voltage flows through them.

Let Q be the amount of charge in each capacitors,

V be the voltage across each capacitors

C be the capacitance of the capacitor.

Using the formula Q = CV where V = Q/C... (1)

For the large capacitor with capacitance of the capacitor C1,

$Q = C_1V_1;$