Question

Algebra 2 test prep pls help​

Answer 1

Answer:

$\frac{\sqrt{117} }{11}$

Step-by-step explanation:

sin²β + cos²β = 1

sin²β = 1 - ( - $\frac{2}{11}$ )²

sin²β = 1 - $\frac{4}{121}$ = $\frac{117}{121}$

sin β > 0 ( Q. ll )

sin β = $\frac{\sqrt{117} }{11}$

Answer 2

sin$\theta_{1}=\frac{\sqrt{117}}{11}$

Answer:

Solution given:

$\bold{Cos \theta_{1}=\frac{-2}{11}}$

squaring both side we get

$\bold{Cos² \theta_{1}=\frac{4}{121}}$

1-sin²$\theta_{1}=\frac{4}{121}$

sin²$\theta_{1}=1-\frac{4}{121}$

sin$\theta_{1}=\sqrt{\frac{117}{121}}$

sin$\theta_{1}=\frac{\sqrt{117}}{11}$