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3 years ago

2x+5y=4 2x-2y=18 using the method of elimination

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

8 0

Answer:

Equation Form:

x=7,y=−2

Step-by-step explanation:

Multiply each equation by the value that makes the coefficients of x

opposite.

(−1)⋅(2x+5y)=(−1)(4)

2x−2y=18

Simplify.

−2x−5y=−4

2x−2y=18

Add the two equations together to eliminate x

from the system.

(−2x−5y=−4) +(2x−2y=18) = (-7y=14)

Divide each term by −7 and simplify.

y=−2

Substitute the value found for y into one of the original equations, then solve for x.

x=7

The solution to the independent system of equations can be represented as a point. (7,−2)

The result can be shown in multiple forms.

Point Form:

(7,−2)

Equation Form:

x=7,y=−2

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Can someone please help me factor this

Dmitry_Shevchenko [17]

Answer:

$\huge\boxed{\bf\:1}$

Step-by-step explanation:

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \times \frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }$

Take $\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 }$ & factorise it at first.

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \\= \frac{\left(x-3\right)\left(x-1\right)}{\left(x-4\right)\left(x-3\right)}\\= \frac{x-1}{x-4}$

Now factorise the next set : $\frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }$ .

$\frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }\\= \frac{\left(x-4\right)\left(x+6\right)}{\left(x-1\right)\left(x+6\right)}\\= \frac{x-4}{x-1}$

Now, multiply the two simplified results.

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \times \frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }\\= \frac{x-1}{x-4}\times \frac{x-4}{x-1} \\= \frac{\left(x-1\right)\left(x-4\right)}{\left(x-4\right)\left(x-1\right)} \\= \boxed{\bf\: 1}$

$\rule{150pt}{2pt}$

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