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Effectus [21]
3 years ago
7

Question 6 of 10

Physics
2 answers:
hram777 [196]3 years ago
8 0

Answer: Choice D) 19.6 J

=======================================

Work Shown:

m = 2 kg = mass

g = 9.8 m/s^2 = acceleration of gravity (approximate)

h = 1 m = height

---------

PE = potential energy

PE = m*g*h

PE = 2*9.8*1

PE = 19.6 J

The vase has approximately 19.6 Joules of potential energy.

We didn't have to make any conversions because the unit Joule is equivalent to the more complicated unit of kg*m^2/s^2 so it only involves kilograms, meters and seconds. If however the mass was given in say grams (instead of kg), then you'd need to convert to kg.

Marizza181 [45]3 years ago
8 0
D I think is the answer
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What area must the plates of a capacitor be if they have a charge of 5.7uC and an electric field of 3.1 kV/mm between them? O 0.
kirill [66]

Answer:

Area of the plates of a capacitor, A = 0.208 m²

Explanation:

It is given that,

Charge on the parallel plate capacitor, q = 5.7\ \mu C=5.7\times 10^{-6}\ C

Electric field, E = 3.1 kV/mm = 3100000 V/m

The electric field of a parallel plates capacitor is given by :

E=\dfrac{q}{A\epsilon_o}

A=\dfrac{q}{E\epsilon_o}

A=\dfrac{5.7\times 10^{-6}\ C}{3100000\ V/m\times 8.85\times 10^{-12}\ F/m}

A = 0.208 m²

So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.

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3 years ago
Why do we charge a capacitor under a DC voltage source only?
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Melanie watched the path a baseball followed after a pitcher threw it. She noticed that the ball traveled horizontally away from
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Explanation:

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4 years ago
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-f
Sati [7]
On the moon, the gravitational acceleration is 1/6 of 9.8 m/s², so
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Launch speed = 35 m/s
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The horizontal velocity is
u = 35*cos(27) = 31.1852 m/s
The vertical launch velocity is
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Part A
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t = v/g = 15.8897/1.6333 = 9.7286 s
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4 years ago
During a baseball game, a batter hits a pop-up to a fielder 93 m away.The acceleration of gravity is 9.8 m/s2.If the ball remain
velikii [3]

Explanation:

It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m

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Time of flight : T=\dfrac{2v\sin\theta}{g}

5.4=\dfrac{2v\sin\theta}{g}\\\\v\sin\theta=\dfrac{5.4\times 9.8}{2}\\\\v\sin\theta=26.46

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H=\dfrac{(v\sin\theta)^2}{2g}\\\\H=\dfrac{(26.46)^2}{2\times 9.8}\\\\H=35.72\ m

So, it will rise to a height of 35.72 m.

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4 years ago
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