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Nitella [24]
2 years ago
10

susan and joe push a table 18 meters down a hall by exerting a force of 200 newtons (n). what is the total amount of work done o

n the table? 1600 joules 1800 joules 2000 joules 3600 joules
Physics
1 answer:
prisoha [69]2 years ago
3 0

Answer:

3600joules

Explanation:

formula :W=FS

W=work done (J)

F=force (N)

S=displacement moved in the direction of force (m)

200N×18m

=3600J

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IRINA_888 [86]

Answer:

Inertia

Explanation:

When the planes moves downward a speed, the weight of the person will decrease a bit due to the amount of g decreases for that particular instant. The person is now experiencing a less than actual weight called as apparent weight due to the upward superposition of inertia on the body as we can see in w = m g .

7 0
3 years ago
A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t
Luda [366]

Answer:

Approximately 0.29\; {\rm m \cdot s^{-1}}.

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass m and velocity v is p = m\, v.

The momentum of the two trolleys before the collision would be:

  • 4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}.
  • 3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}.

Thus, the total momentum of the two trolleys right before the collision would be 2\; {\rm kg \cdot m \cdot s^{-1}}.

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}.

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass m = 7\; {\rm kg} would continue to be v = 2\; {\rm kg \cdot m \cdot s^{-1}} shortly after the collision.

Rearrange the equation p = m\, v to find the velocity of the two trolleys combined:

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}.

6 0
2 years ago
Question 30
stellarik [79]

Answer: 0.69\°

Explanation:

The angular diameter \delta of a spherical object is given by the following formula:

\delta=2 sin^{-1}(\frac{d}{2D})

Where:

d=16 m is the actual diameter

D=1338 m is the distance to the spherical object

Hence:

\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})

\delta=0.685\° \approx 0.69\° This is the angular diameter

3 0
3 years ago
A 1100 kg car is traveling around a flat 82.3 m radius curve. The coefficient of static friction between the car tires and the r
Novay_Z [31]

Answer:

The maximum speed of car will be 20.5m/sec

Explanation:

We have given mass of car = 1100 kg

Radius of curve = 82.3 m

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We have to find the maximum speed of car

We know that at maximum speed centripetal force will be equal to frictional force m\frac{v^2}{r}=\mu _srg

v=\sqrt{\mu _srg}=\sqrt{0.521\times 82.3\times 9.8}=20.5m/sec

So the maximum speed of car will be 20.5m/sec

8 0
3 years ago
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ASAP HELP PLZZZZZZZZZZWhich of the following happens when normal force and gravitational force acting on an object are unbalance
wel

Answer:

up and down I think

Explanation:

3 0
3 years ago
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