Answer:
There would be 10 quarters and 23 dimes.
Step-by-step explanation:
There are generally two methods to solving this type of problem. (1) is guess and check, where you try different amounts of dimes and quarters in combinations of 33 coins until you reach an amount of $4.80. However, we can also solve the problem algebraically using two equations and two variables. In this case, 'd' = amount of dimes and 'q' = amount of quarters. We know that there are 33 total coins, or d + q = 33. We also know that the amount of the coins is $4.80, or .10d + .25q = 4.80. Solving the first equation for 'q', we get q = 33 - d. We can then substitute this expression for 'd' in the second equation to solve for d: .10d + .25(33 - d) = 4.80 or .10d + 8.25 - .25d = 4.80. Combining like terms and using inverse operations, first subtraction then division, we get d = 23. If there are 23 dimes, then there must be 10 quarters, for a total of 33 coins or $2.30 in dimes and $2.50 in quarters.
The best and most correct answer among the choices provided by your question is the fourth choice or letter D. The probability is 4/5.
<span>P ( canadian)= 3/15 = 1/5
On the other hand, P (not canadian) = 1 - 1/5 = 4/5</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
Rewrite the term
Expand each term so we have
Use the fact that
Use the fact that when a is an even number
Simplify
Let me know if you need any clarifications, thanks!
18 sleep more than 540 and 10 sleep less than 540 hope this helps