Answer:
The value of the ve = 9m/sec
Step-by-step explanation:
From the given formula, it can be conclude that this is evenly accelerated movement.
First I will rewrite given formula
vi = √ ve∧2 - 2ad First we will square on both sides and get
vi∧2 = ve∧2 - 2ad Now we will add monom (+2ad) to both sides and get
vi∧2 + 2ad = ve∧2 -2ad + 2ad =>
ve∧2 = vi∧2 +2ad Now we will rooted both sides and get
ve = √vi∧2 + 2ad
Now we will replace given data vi=7m/sec, a=8m/s∧2 and d=2m in the last formula
ve= √7∧2 + 2*8*2 = √49+32 = √81 = 9
ve= 9m/sec
Good luck!!!
Answer:
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Step-by-step explanation:
Answers :D18
Step-by-step explanation:
Because I did the marh
This question is incomplete.
The complete question says;
The two-way table shows the number of hours students studied and whether they studied independently or with a study group.
What is the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently?
a) 0.4 c) 0.25
b) 0.33 d) 0.11
Table is attached as image
Answer: C (0.25)
The number of students that studied for more than 2 hours as given in the table are 4.
The total number of people that studied independently include those that studied less than 2 hours and those that studied for more than 2 hours.
Those that studied less than 2 hours independently are 12.
Those that studied more than 2 hours independently are 4.
Hence the total number of people that studied independently is 16.
Therefore the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently would be = 4/16 = 1/4 = 0.25.