Answer:
The elastic potential is 1/2 as much.
Explanation:
The reason I say this is because of you take a new rubber band, after stretching the first time, all the way until it doesn't snap, you stretch it again and there's not as much resistance as when it was new.
I hope this helps.
W= 540 N
M=?
G= 9.8
W=mg
540=mx9.8
M=540\9.8
M=55.10
Question 1's answer is, if we change the length of the string allowed to vibrate, then the frequency (and pitch) of the string vibration will change. This is because the tension of the string determines the pitch.
Question 2's answer is 2. This can be solved by doing simple division. 30/15 = 2.
Question 3's answer is short bars. Each bar on a xylophone produces a different pitch; the shorter the bar, the higher the pitch.
Hope this helps.
Answer:
The speed of sound can be gotten by simply finding the average of the results.
=0.756s
It is advisable for the students to repeat 5 times because it allows them to (a) estimate the variability of the results (how close to each other they are) and (b) to increase the accuracy of the estimate.