You can tell a lot about an object that's not moving,
and also a lot about the forces acting on it:
==> If the box is at rest on the table, then it is not accelerating.
==> Since it is not accelerating, I can say that the forces on it are balanced.
==> That means that the sum of all forces acting on the box is zero,
and the effect of all the forces acting on it is the same as if there were
no forces acting on it at all.
==> This in turn means that all of the horizontal forces are balanced,
AND all of the vertical forces are balanced.
Horizontal forces:
sliding friction, somebody pushing the box
All of the forces on this list must add up to zero. So ...
(sliding friction force) = (pushing force), in the opposite direction.
If nobody pushing the box, then sliding friction force = zero.
Vertical forces:
gravitational force (weight of the box, pulling it down)
normal force (table pushing the box up)
All of the forces on this list must add up to zero, so ...
(Gravitational force down) + (normal force up) = zero
(Gravitational force down) = -(normal force up) .
Explanation:
Hey there!
Here,
Pascal is a unit of pressure.

Now, As per the formula the units are:
kg, m and s^2.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
<span>about $137.00 (plug n play) http://store.racer-union.com try this web site they are the cheapest by about 100 dollars.</span>
A) The power delivered to the lines is

And the voltage at which the lines work is

Since the power delivered is the product between the voltage and the current:

We can find the current flowing in the lines:

b) The voltage change along each line can be found by using Ohm's law:

c) The power wasted as heat along each line is given by:

And since we have 2 lines, the total power wasted as heat in both lines is
Answer:

Explanation:
Using the angular formulas can determine the radius using both values neutron star and the the knowing star so



I=Inertia of the star
w=angular velocity


Notice the angular velocity determinate by the time and the Inertia have the radius value so





