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3 years ago

Find the sum or difference -2 + (-3) =

Mathematics

2 answers:

sweet [91]3 years ago

8 0

Answer:

-5

Step-by-step explanation:

Hope it helps.......................................

wel3 years ago

7 0

The answer would be -5

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Express in the form n:1 give n as a decimal 21:12

Makovka662 [10]

$1.75:1$ which is similar to n:1 where $n=1.75$

Step-by-step explanation:

Here we have to Express in the form n:1 give n as a decimal 21:12 . Let's find out:

Given ratio as 21:12 . Let's convert it into n:1 , where n is decimal

⇒ $21:12$

⇒ $\frac{21}{12}$

⇒ $\frac{3(7)}{3(4)}$

⇒ $\frac{7}{4}$

⇒ $\frac{\frac{7}{4}}{\frac{4}{4}}$ { dividing denominator & numerator by 4 }

⇒ $\frac{\frac{7}{4}}{1}$

⇒ $\frac{1.75}{1}$

⇒ $1.75:1$ which is similar to n:1 where $n=1.75$

7 0

3 years ago

Robert plays cricket. He hit the ball in such a way that it goes up 180 feet

PilotLPTM [1.2K]

Answer:

4 feet per second

Step-by-step explanation:

Hi there!

$v=D/t$ where v is velocity (speed), D is distance and t is time

Plug in the known values (D=180 feet, t=45 seconds)

$v=180/45\\v=4$

Therefore, the speed of the ball is 4 feet per second.

I hope this helps!

4 0

3 years ago

Read 2 more answers

Consider a t distribution with 24 degrees of freedom. Compute P(-1.27˂t˂1.27) . Round your answer to at least three decimal plac

DENIUS [597]

Answer:

Step-by-step explanation:

Use the calculator provided to solve the following problems.
Consider a t distribution with 24 degrees of freedom. Compute P(-1.27˂t˂1.27) . Round your answer to at least three decimal places.
Consider a t distribution with 5 degrees of freedom. Find the value of c such that P(t≤c)=0.05 . Round your answer to at least three decimal places.

3 0

3 years ago

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

4 0

3 years ago

D O,K = (0, 2) → (0, 6) The scale factor is _____.

Law Incorporation [45]

Answer: the answer will be 3

Step-by-step explanation:

3 0

3 years ago