An object is launched vertically in the air at 36.75 meters per second from a 6-meter-tall platform. Using the projectile motion
model h(t) = -4.912 + vot+ hy, where h(t)
is the height of the projectile t seconds after its departure, Vo is the initial velocity in meters per second, and he is the initial height in meters, determine how long it
ersity
will take for the object to reach its maximum height. What is the maximum height?
The object will reach its maximum height in
seconds
1 answer:
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Answer:
i think maybe D
Step-by-step explanation:
Normally a equation has to have an equal sign and all the numbers add up
N in (-oo:+oo)
-13 = n-8 // - n-8
8-n-13 = 0
-n-5 = 0 // + 5
-n = 5 // * -1
n = -5
n = -5
Answer:
23,936
Step-by-step explanation:
so get your 17600 times it by 0.36 which gets you 6,336 then add that to 17,600 =23,936
That's how you get your answer
Perimeter = 2(10+20) = 60feet
60ft fencing material is needed
The numbers are being multiplied by 7
.5 • 7 = 3.5
3.5 • 7 = 24.5
24.5 • 7 = 171.5
etc
