An object is launched vertically in the air at 36.75 meters per second from a 6-meter-tall platform. Using the projectile motion
model h(t) = -4.912 + vot+ hy, where h(t)
is the height of the projectile t seconds after its departure, Vo is the initial velocity in meters per second, and he is the initial height in meters, determine how long it
ersity
will take for the object to reach its maximum height. What is the maximum height?
The object will reach its maximum height in
seconds
1 answer:
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Hello,
Al 'Kashi theorem says:
a²=4²+7²-2*4*7*cos 20°=12.37721...
==>a=3.518126381...≈3.5 ==>False.
