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KATRIN_1 [288]
3 years ago
14

Can you fill in the blanks. Thx

Mathematics
1 answer:
maria [59]3 years ago
4 0

Answer:

Answer is below

Step-by-step explanation:

Download docx
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30.1

Step-by-step explanation:

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If 1 inch is 500 miles, then 4 inches is how many miles?
tiny-mole [99]

Answer:

2,000 miles

Step-by-step explanation:

We are given:

1 inch=500 miles

This can be rewritten as:

\frac{500 miles}{1inch}

This is representative of a unit rate, as we have a 1 in the denominator. To calculate the number of miles in 4 inches, simply multiply the unit rate by 4:

\frac{500 miles}{1inch}*4=

\frac{2000 miles}{4 inches}

This can rewritten as:

4inches=2000miles

Therefore, there are 2,000 miles in 4 inches.

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We can check our solution by simplifying the fraction \frac{2000 miles}{4 inches} by dividing both 2000 and 4 by 4 to see if we achieve the unit rate:

\frac{500 miles}{1 inch}

Since this is in fact the unit rate, our solution is correct!

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Please help me???? 25 points
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Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
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