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Lera25 [3.4K]
3 years ago
8

If a 3-kg rock is thrown at a speed of 2 m/s in a gravity-free environment (presuming one could be found), then an unbalanced fo

rce of 6 N would be required to keep the rock moving at a constant speed.
Select one:
a. False
b. True
Physics
2 answers:
lbvjy [14]3 years ago
5 0

That's false.

NO FORCE is required to keep an object moving at a constant speed.

Katarina [22]3 years ago
3 0

Answer:

a. False

Explanation:

For an object to be moving at a constant velocity, a net force of 0 N would be required.

Newton's 1st Law of Motion states that an object will remain at rest unless acted upon by an unbalanced force, and an object will remain in motion unless acted upon by an unbalanced force.

Therefore, the unbalanced force of 6 N would not allow the rock to maintain its constant speed.

The answer to this question is A) False.

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Calculate the total displacement of a mouse walking along a ruler, if it begins at the x=5cm, and then does the following: It wa
Lana71 [14]
<span>To begin, the mouse walks from 5 to 12 cm, for a displacement of 7 cm. Next, it walks 8 cm in the opposite direction, for a total displacement of (7 + [-8]) or (-1) cm. This leaves the mouse on 4 cm, and then it walks from there to the 7cm location, for a displacement of 7-4 or +3 cm. Adding 3cm to -1cm gives a final displacement of +2cm.</span>
6 0
4 years ago
A stationary 6-kg shell explodes into three pieces. One 4.0 kg piece moves horizontally along the negative x-axis. The other two
natta225 [31]

Answer:

-15 m/s

Explanation:

The computation of the velocity of the 4.0 kg fragment is shown below:

For this question, we use the correlation of the momentum along with horizontal x axis

Given that

Weight of stationary shell = 6 kg

Other two fragments each = 1.0 kg

Angle = 60

Speed = 60 m/s

Based on the above information, the velocity = v is

1\times 60 \times cos\ 60 + 1\times 60 \times cos\ 60 - 4\ v = 0

\frac{60}{2} + \frac{60}{2} - 4\ v = 0

v = \frac{60}{4}

= -15 m/s

4 0
3 years ago
What are the answers please help
aleksandr82 [10.1K]

Answer:

a.) The main scale reading is 10.2cm

b.) Division 7 = 0.07

c.) 10.27 cm

d.)  10.31 cm

e.)  10.24 cm  

Explanation:

The figure depicts a vernier caliper readings

a.) The main scale reading is 10.2 cm

The reading before the vernier scale

b.) Division 7 = 0.07

the point where the main scale and vernier scale meet

c.) The observed readings is

10.2 + 0.07 = 10.27 cm

d.) If the instrument has a positive zero error of 4 division

correct reading = 10.27 + 0.04 = 10.31cm

e.)  If the instrument has a negative zero error of 3 division

correct reading = 10.27 - 0.03 = 10.24cm  

3 0
3 years ago
A wave has an amplitude of 0.2 cm.
Anettt [7]
The distance between the resting point and maximum height of the wave is 0.2 cm.

The amplitude is measured from the resting point up to the highest point of the wave.
3 0
3 years ago
1 point
Alecsey [184]

Answer:

Explanation:

ℎ

7 0
3 years ago
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