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3 years ago

What are two things that happen to the sugars that are made by the plant during photosynthesis?

Physics

1 answer:

Elena-2011 [213]3 years ago

5 0

Answer:

The sugars produced by photosynthesis can be stored, transported throughout the tree, and converted into energy which is used to power all cellular processes. Respiration occurs when glucose (sugar produced during photosynthesis) combines with oxygen to produce useable cellular energy.

Explanation:

I think this is correct lol.

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Calculate the orbital speed (in m/s) of a satellite that circles the Earth with a time period of 12.00 hours. The mass of the Ea

Hoochie [10]

Answer:

$v = 3869 m/s$

Explanation:

As we know that the orbital speed of the satellite is given as

$v = \sqrt{\frac{GM}{r}}$

also we know that

time period of the revolution is given as

$T = \frac{2\pi r}{v}$

now from above equation we know that

$T = \frac{2\pi (\frac{GM}{v^2})}{v}$

$T = \frac{2\pi GM}{v^3}$

so we will have

$v = (\frac{2\pi GM}{T})^{1/3}$

now plug in all data in this equation

$v = (\frac{2\pi (6.67 \times 10^{-11})(5.97 \times 10^{24})}{12 \times 3600})^{1/3}$

$v = 3869 m/s$

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3 years ago

An object with a mass of 5.0 kg accelerates 2.8 m/s2 towards right when an unknown force is applied to it. What is the amount of

RoseWind [281]

Answer:

Explanation:

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3 years ago

A sound can be ________ or _________.

marin [14]

A.
Sorry if it’s wrong

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3 years ago

An electron in a hydrogen atom undergoes a transition from the n = 3 level to the n = 6 level. To accomplish this, energy, in th

Harlamova29_29 [7]

Answer: $1.816\times 10^{-19} J$

Explanation:

Given

$E=\frac{hc}{\lambda }$

$E=2.18\times 10^{-18}(\frac{1}{n_1^2}-\frac{1}{n_2^2})$

where h=Planck constant

c=speed of light

$E=2.18\times 10^{-18}(\frac{1}{3^2}-\frac{1}{6^2})$

$E=2.18\times 10^{-18}\times \frac{1}{12}$

$E=1.816\times 10^{-19} J$

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3 years ago

A 3500 kg truck is parked on a 7.0∘ slope. How big is the friction force on the truck?

Arada [10]

Answer:

4180 N

Explanation:

In order to keep the truck balanced and stationary, the force of friction on the truck must be equal to the component of the weight of the truck acting parallel to the slope.

The component of the weight of the truck acting parallel to the slope is:

$mg sin \theta$

where

m = 3500 kg is the mass of the truck

g = 9.8 m/s^2 is the acceleration of gravity

$\theta=7.0^{\circ}$ is the angle of the slope

Therefore, the force of friction must be equal to

$F=(3500)(9.8)(sin 7.0^{\circ})=4180 N$

6 0

3 years ago

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