Both rocks hit the ground at the same time and at the same distance from the base of the cliff. Option A is correct.
<h3>What is speed ?</h3>
Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its SI unit is m/sec.
If the resistance is ignored, things falling near the Earth's surface have the same estimated acceleration due to gravity of 9.8 meters per second.
As a result, the objects' acceleration is the same, and their velocity is growing at a consistent pace.
So that both rocks hit the ground at the same time and at the same distance from the base of the cliff.
Hence, option A is correct.
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Kinetic energy is mass times velocity square mv^2 (0.75*4^2=12)
Answer:
(a). The electric potential at 1.650 cm is
.
(b). The electric potential at 2.81 cm is
.
Explanation:
Given that,
Radius of sphere R=2.81 cm
Charge = +2.35 fC
Potential at center of sphere

(a). We need to calculate the potential at a distance r = 1.60 cm
Using formula of potential difference






The electric potential at 1.650 cm is
.
(b). We need to calculate the potential at a distance r = R
Using formula of potential difference



The electric potential at 2.81 cm is
.
Hence, This is the required solution.
Explanation:
initial velocity(u) = 90 km/s = 25 m/s
time (t) = 5 sec
mass (m) = 200 kg
final velocity (v) = 0 m/s
v = u + at
0 = 25 + a * 5
-25 = 5 a
-5 = a
Therefore acceleration = -5m/s²
Force = mass * acceleration
F = 200*-5
F = -1000 N
Answer:
<h2>
m/s ^2</h2><h2 />
Explanation:
Solution,
When a certain object comes in motion from rest, in the case, initial velocity = 0 m/s
Initial velocity ( u ) = 0 m/s
Final velocity ( v ) = 72 km/h ( Given)
We have to convert 72 km /h in m/s


m/s
Final velocity ( v ) = 20 m/s
Time taken ( t ) = 2 seconds
Acceleration (a) = ?
Now,
we have,



m/s ^2
Hope this helps...
Good luck on your assignment..