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Readme [11.4K]
3 years ago
6

What are two things that happen to the sugars that are made by the plant during photosynthesis?

Physics
1 answer:
Elena-2011 [213]3 years ago
5 0

Answer:

The sugars produced by photosynthesis can be stored, transported throughout the tree, and converted into energy which is used to power all cellular processes. Respiration occurs when glucose (sugar produced during photosynthesis) combines with oxygen to produce useable cellular energy.

Explanation:

I think this is correct lol.

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A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person  standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

7 0
3 years ago
A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising th
erik [133]

Answer:

P = 36068.7 Watt

Explanation:

As we know that average power is the ratio of total work done and total time interval

so we will have

Power = \frac{Total \: Work}{time}

now we know that

Work = \frac{1}{2}mv^2 + mgh

W = \frac{1}{2}(700)(11^2) + 700(9.8)(9.6)

so we will have

W = 42350 J + 68856 J

W = 108206 J

now power is given as

P = \frac{108206}{3}

P = 36068.7 Watt

6 0
3 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
An electron (charge = –1.6 x 10–19 C) is moving at 3.0 x 105 m/s in the positive x direction. A magnetic field of 0.80 T is in t
Marta_Voda [28]

Answer:

F = 3.84*10^-34N ^j

Explanation:

In order to calculate the magnetic force on the electron you use the following formula:

\vec{F}=q\vec{v} \ X\ \vec{B}       (1)

q: charge of the electron = -1.6*10^-19C

B: magnitude of the magnetic field = 0.80T

v: speed of the charge = 3.0*10^5 m/s

The direction of the motion of the electron is in the +i^ direction (+x direction). The magnetic field is in the +^k direction (+z direction).

The cross product between these unit vectors, by taking into account the minus sign of the charge, is given by:

-^i X ^k = ^j

The magnetic force is in the ^j direction (+y direction).

The magnitude of the magnetic force is:

F=qvB=(1.6*10^{-19}C)(3.0*10^5m/s)(0.80T)=3.84*10^{-34}N

The magnetic force on the electron has a magnitude of 3.84*10^-34N in the +y direction

7 0
3 years ago
A can of tuna, starting from rest, is dropped off a building. If it is only being pulled down by gravity (-9.8 m/s2) and it hits
tia_tia [17]

Answer:

<h3>50.23m</h3>

Explanation:

The distance talks about how far an object has travelled.

Given

9 = -9.8m/s²

t = 3.2s

to get the distance Δx, we will use the formula;

S = ut+1/2gt²

S = 0(3.2)+1/2(-9.8)(3.2)²

S = 0-4.905(10.24)

S = -50.23m

Hence the can of tuna drop by 50.23m

3 0
3 years ago
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