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Artist 52 [7]
3 years ago
9

For fish to survive in your aquarium, you need to have a saturated solution of oxygen in the water. Suppose your aquarium holds

250L of water. How many grams of oxygen do you need to pump into the tank?
Chemistry
1 answer:
solmaris [256]3 years ago
7 0

Answer:

The mass of oxygen needed to be pumped in the aquarium is 10 g

Explanation:

Here the value of the degree of solubility of oxygen in water is sought

The solubility of oxygen in fresh water is approximately 1.22 × 10⁻³ mol·dm⁻³ which is equivalent to approximately 40 mg/L

The volume of water the aquarium holds = 250 L

The mass of oxygen required = The solubility of oxygen in water × (The volume of water in the aquarium)

Therefore, the mass of oxygen needed to be pumped in the aquarium = 40 mg/L × 250 L = 10,000 mg

1,000 mg = 1 g

∴ 10,000 mg = 10 g

The mass of oxygen needed to be pumped in the aquarium = 10,000 mg = 10 g.

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Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the
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Answer:

1.2\times 10^{-2}

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